Given:
Figures A, B and C.
To find:
The order of the figures and volume of each figure.
Solution:
<u>Figure A:</u>
Length = 10, Width = 2 and Height = 2
Volume of A = length × width × height
= 10 × 2 × 2
Volume of A = 40 cubic units
<u>Figure B:</u>
Length = 3, Width = 3 and Height = 1
Volume of B = length × width × height
= 3 × 3 × 1
Volume of B = 9 cubic units
<u>Figure C:</u>
Length = 6, Width = 3 and Height = 3
Volume of C = length × width × height
= 6 × 3 × 3
Volume of C = 54 cubic units
Order from greatest to least:
54 < 40 < 9
C < A < B
Hence Kurry said the correct answer.
Answer:
x=7
Step-by-step explanation:
4x+12=40
-12
4x=28/4
Answer:
Step-by-step explanation:
area of top=7×6=42 yd²
area of bottom=3×6=18 yd²
area of two rectangles=2[4×6]=48 yd²
area of two trapezoids=2[1/2(7+3)×3.5]=35 yd²
total surface area=42+18+48+35=143 yd²
Answer:
The relation is not a function
The domain is {1, 2, 3}
The range is {3, 4, 5}
Step-by-step explanation:
A relation of a set of ordered pairs x and y is a function if
- Every x has only one value of y
- x appears once in ordered pairs
<u><em>Examples:</em></u>
- The relation {(1, 2), (-2, 3), (4, 5)} is a function because every x has only one value of y (x = 1 has y = 2, x = -2 has y = 3, x = 4 has y = 5)
- The relation {(1, 2), (-2, 3), (1, 5)} is not a function because one x has two values of y (x = 1 has values of y = 2 and 5)
- The domain is the set of values of x
- The range is the set of values of y
Let us solve the question
∵ The relation = {(1, 3), (2, 3), (3, 4), (2, 5)}
∵ x = 1 has y = 3
∵ x = 2 has y = 3
∵ x = 3 has y = 4
∵ x = 2 has y = 5
→ One x appears twice in the ordered pairs
∵ x = 2 has y = 3 and 5
∴ The relation is not a function because one x has two values of y
∵ The domain is the set of values of x
∴ The domain = {1, 2, 3}
∵ The range is the set of values of y
∴ The range = {3, 4, 5}
