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Tom [10]
3 years ago
9

Help with this question, please.

Mathematics
2 answers:
tamaranim1 [39]3 years ago
7 0

For this case we have that by definition:

The limit of a constant function of the form y = f (x), where f (x) = c, is the same constant, whatever the value to which the limit tends.

Thus, the limit of "5" when x tends to "2", results in "5".

Answer:

5

Option A


PIT_PIT [208]3 years ago
5 0

The limit of any constant function is the value of the constant, so the limit is just 5.

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Amelie is making a recipe that uses 1 3/4 cups flour. She is making 2 1/2 times the original recipe.
elixir [45]

Answer:

She would need 4\frac{3}{8} flour to make  2\frac{1}{2} times the recipe.

Step-by-step explanation:

To make 1 recipe Amelia uses = 1 \frac{3}{4}\ cups of flour.

So, to make 2\frac{1}{2} times the recipe she would need =1 \frac{3}{4}\times 2\frac{1}{2}.

We evaluate the above mixed numbers by converting them to fraction(by multiplying denominator with whole number and adding to numerator and write as fraction of same denominator.).

=\frac{7}{4}\times \frac{5}{2}

=\frac{35}{8}

Then converting back to mixed number (by dividing the numerator by denominator and writing the quotient as the whole number and the remainder as fraction with same denominator.

\frac{35}{8}=4\frac{3}{8}

So, she would need 4\frac{3}{8} flour to make  2\frac{1}{2} times the recipe.

7 0
3 years ago
2.Beth is 6 years younger than<br>twice her brother's age. How old is<br>Beth?​
murzikaleks [220]
Beth would be four years old
8 0
3 years ago
Pls help i will mark brainliest
aksik [14]

Answer:

the answer is the first one I think but I'm pretty sure

6 0
3 years ago
What’s the axis of symmetry for f(x)=2(x-3)^2+6
Nadya [2.5K]

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3 years ago
In a list of five consecutive odd integers, the sum of the first and double the last is 139. What is the largest sum?
Leviafan [203]

Answer: 49

Step-by-step explanation:

From your question, I think you mean the largest number. The answer is given below.

Let the five consecutive odd numbers be:

a, a+2, a+4, a+6 and a+8.

Thee sum of the first and double the last is 139. This can be written as:

a + 2(a+8) = 139

a + 2a + 16 = 139

3a + 16 = 139

3a = 139 - 16

3a = 123

a = 123/3

a = 41

The first number = 41

The largest number = a+8 = 41 + 8 = 49.

7 0
3 years ago
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