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Natalija [7]
3 years ago
13

16. An object has a mass of 13.5 kilograms. What force is required to accelerate it to a rate of 9.5 m/s2?

Physics
2 answers:
Firdavs [7]3 years ago
7 0

Answer: The correct answer is option D.

Explanation:

Mass of an object = 13.5 kg

Rate of the acceleration = 9.5 m/s^2

Force=Mass\times Acceleration=ma(Newton's second law of motion)

Force=13.5 kg\times 9.5 m/s^2=128.25 kg m/s^2=128.25 Newtons

128.25 Newtons of force is required to accelerate it to a rate of 9.5 m/s^.

Hence,the correct answer is option D.

Ivahew [28]3 years ago
3 0

We can solve the problem by using Newton's second law of motion:

F=ma

where F is the force required to accelerate the object, m is its mass, and a is the acceleration.

In this problem, we are told that the mass of the object is m=13.5 kg, while its acceleration is a=9.5 m/s^2. Substituting these data into the equation, we find the force required to produce these acceleration:

F=ma=(13.5 kg)(9.5 m/s^2)=128.25 N

So, the correct answer is

D. 128.25 N

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A uniform metal tube of length 5m and mass 9kg is suspended by two vertical wires attached at 50cm and 150cm respectively from t
Elena-2011 [213]

Answer:

force (tension) of 29.4 N (upward)  in 100 cm

force (tension) of 58.4 N (upward)  in 200 cm

Explanation:

Given:

Length of tube = 5 m (500 cm)

Mass of tube = 9

Suspended vertically from 150 cm and 50 cm.

Computation:

Force = Mass × gravity acceleration.

Force = 9.8 x 9

Force = 88.2 N

So,

Upward forces = Downward forces

D1 = 150 - 50 = 100 cm

D2 = 150 + 50 = 200 cm

And F1 = F2

F1 x D1 = F2 x D2

F1 x 100 = F2 x 200

F = 2F

Total force = Upward forces + Downward forces

3F = 88.2

F = 29.4 and 2F = 58.8 N

force (tension) of 29.4 N (upward)  in 100 cm

force (tension) of 58.4 N (upward)  in 200 cm

4 0
4 years ago
A mine elevator cage with a mass of 2.5 tons empty is descending at a rate of 32 km/hr when the hoist mechanism jams and stops s
True [87]

Answer:

σ = 4.1 MPa

Explanation:

Given that

m= 2.5 kg

v=  32 km.hr

v= 8.88 m/s

The kinetic energy of the mass ,KE

KE = mv²/2

KE = 2.5 x 8.88²/2

KE= 98.56 J    -------1

The strain energy of the string

E=\dfrac{\sigma^2}{2E}AL

E=\dfrac{\sigma^2}{2\times 84,000\times 10^6}\times 6.5\times 10^{-4}\times 1500

E={\sigma^2}\times {5.80\times 10^{-12}} ----2

KE= E

98.56={\sigma^2}\times {5.80\times 10^{-12}}

\sigma =\sqrt{\dfrac{98.56}{5.80\times 10^{-12}}}

σ = 4.1 MPa

4 0
3 years ago
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