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3 years ago

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If the mass of both weights is 225 gm, the first mass is located 20∘ north of east, the second mass is located 20∘ south of east

, and the transducer sensitivity is 0.5 volts/Newton, how large a voltage do you expect to measure? Assume the transducer has been properly zeroed so that V = 0 when F3=0. Please express your answers with 1 decimal place.

1 answer:

Montano1993 [528]3 years ago

7 0

Answer:

The voltage is 2.114 V.

Explanation:

Given that,

Mass of both weights = 225 gm

Transducer sensitivity = 0.5 V/N

The first mass is located 20∘ north of east, the second mass is located 20∘ south of east,

We need to calculate the net equivalent force

Using formula of force

$F_{3}=m_{1}g\cos\theta+m_{2}g\cos\theta$

$F_{3}=2mg\cos\theta$

Put the value into the formula

$F_{3}=2\times0.225\times10\cos20^{\circ}$

$F_{3}=4.228\ N$

We need to calculate the voltage

Using formula of voltage

$Voltage =sensitivity\times F_{3}$

Put the value into the formula

$Voltage=0.5\times4.228$

$Voltage =2.114\ V$

Hence, The voltage is 2.114 V.

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