NOTE: The diagram is attached to this solution
Answer:
The acceleration of point A = 14.64 ft/s²
Explanation:
By proper analysis of the diagram, acceleration of point A will be: (Check the free body diagram attached)
Weight, W = mg
g = 32.2 ft/s²
m = W/g
but 
This is the period of a pendulum. Notice the mass doesn't matter. Plugging in your values and 9.81m/s^2 for g, gives
T=10.7731s.
Answer with explanation:
The given vectors in are reduced to their componednt form as shown
For vector A it can be written as
Similarly vector B can be written as
Hence The sum and difference is calculated as
The direction is given by
with positive x axis.
Similarly
The direction is given by
with positive x axis.
Answer:
Explanation:
Total momentum of the system before the collision
.5 x 3 - 1.5 x 1.5 = -0.75 kg m/s towards the left
If v be the velocity of the stuck pucks
momentum after the collision = 2 v
Applying conservation of momentum
2 v = - .75
v = - .375 m /s
Let after the collision v be the velocity of .5 kg puck
total momentum after the collision
.5 v + 1.5 x .231 = .5v +.3465
Applying conservation of momentum law
.5 v +.3465 = - .75
v = - 2.193 m/s
2 ) To verify whether the collision is elastic or not , we verify whether the kinetic energy is conserved or not.
Kinetic energy before the collision
= 2.25 + 1.6875
=3.9375 J
kinetic energy after the collision
= .04 + 1.2 =1.24 J
So kinetic energy is not conserved . Hence collision is not elastic.
3 ) Change in the momentum of .5 kg
1.5 - (-1.0965 )
= 2.5965
Average force applied = change in momentum / time
= 2.5965 / 25 x 10⁻³
= 103.86 N
