A uniform metal tube of length 5m and mass 9kg is suspended by two vertical wires attached at 50cm and 150cm respectively from t
1 answer:
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Answer:
Explanation:
Given that:
- force applied,
- displacement,
(length of a tennis court)
- time taken for pushing, t = 40 s
Since, work is given by:
Now, power is given as:
Calories consumed is:
Answer:
xmax = 9.5cm
Explanation:
In this case, the trajectory described by the electron, when it enters in the region between the parallel plates, is a semi parabolic trajectory.
In order to find the horizontal distance traveled by the electron you first calculate the vertical acceleration of the electron.
You use the Newton second law and the electric force on the electron:
(1)
q: charge of the electron = 1.6*10^-19 C
m: mass of the electron = 9.1*10-31 kg
E: magnitude of the electric field = 4.0*10^2N/C
You solve the equation (1) for a:
Next, you use the following formula for the maximum horizontal distance reached by an object, with semi parabolic motion at a height of d:
(2)
Here, the height d is the distance between the plates d = 2.0cm = 0.02m
vo: initial velocity of the electron = 4.0*10^6m/s
You replace the values of the parameters in the equation (2):
The horizontal distance traveled by the electron is 9.5cm
Answer:
The work done by the friction force is 11700J
Explanation:
The work done by the friction force is given by:
According to Newton's second law:
So: