A uniform metal tube of length 5m and mass 9kg is suspended by two vertical wires attached at 50cm and 150cm respectively from t
1 answer:
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Answer:
32.3 m/s
Explanation:
The ball follows a projectile motion, where:
- The horizontal motion is a uniform motion at costant speed
- The vertical motion is a free fall motion (constant acceleration)
We start by analyzing the horizontal motion. The ball travels horizontally at constant speed of
and it covers a distance of
d = 165 m
So, the total time of flight of the ball is
In order to find the vertical velocity of the ball, we have now to analyze its vertical motion.
The vertical motion is a free-fall motion, so the ball is falling at constant acceleration; therefore we can use the following suvat equation:
where
is the vertical velocity at time t
is the initial vertical velocity
is the acceleration of gravity (taking downward as positive direction)
Substituting t = 3.3 s (the time of flight), we find the final vertical velocity of the ball:
Answer:
Part a)
When spring compressed by 2 cm
H = 1.47 m
Part b)
When spring is compressed by 4 cm
H = 5.94 m
Explanation:
Part a)
As we know that the spring is compressed and released
so here spring potential energy is converted into gravitational potential energy at its maximum height
So we will have
so we have
Part b)
Similarly when spring is compressed by 4 cm
then we have
so we have