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4 years ago

Answers asap; greatly appreciated

Mathematics

1 answer:

vagabundo [1.1K]4 years ago

6 0

I believe the answer is D

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If f(x)=8x which is the following is the inverse of f(x)

worty [1.4K]

Answer:my=8x

To find the inverse, flip the x and y variables and then solve for y.

x=8y

x/8=8y/8

x/8=y

Final answer: f^-1(x)=x/8

5 0

3 years ago

Find all zeros of the polynomial P(x) = x3 − 2x2 − 3x + 10. Express any non-real roots in the form a + bi.

Strike441 [17]

Answer:

$x = - 2 \: or \: x = 2 - i \: or \: x = 2 + i$

Step-by-step explanation:

The given equation is

$p(x) = {x}^{3} - 2 {x}^{2} - 3x + 10$

We can see that:

$p( - 2) = {( - 2)}^{3} - 2 {( -2) }^{2} - 3( - 2)+ 10$

$p( - 2) = - 8- 8 + 6+ 10 = 0$

This means x=-2 is a zero of p(x).

From the long division in the attachment,

We can rewrite the polynomial as:

${x}^{3} - 2 {x}^{2} - 3x + 10 = (x + 2)( {x}^{2} - 4x + 5)$

We now find solution to the quadratic part:

${x}^{2} - 4x + 5 = 0$

This is given by:

$x = \frac{ - b \pm \sqrt{ {b}^{2} - 4ac} }{2a}$

We plug in the values to get:

$x = \frac{ - - 4 \pm \sqrt{ {( - 4)}^{2} - 4 \times 1 \times 5} }{2 \times 1}$

$x = \frac{ 4 \pm \sqrt{ 16 - 20} }{2 }$

$x = \frac{ 4 \pm \sqrt{ - 4} }{2 }$

$x = \frac{ 4 \pm2i}{2 } \\ x = 2 \pm \: i \\ x = 2 - i \: or \: x = 2 + i$

Therefore all solutions are:

$x = - 2 \: or \: x = 2 - i \: or \: x = 2 + i$

4 0

3 years ago

-0.615,-5/8,-0.63 least to greatest

Zarrin [17]

-0.63,-5/8,-0.615 I hope this is helpful and I'm pretty sure it's correct.

4 0

3 years ago

Read 2 more answers

A ∪ B= {a,b,c,d,e,f} and B= {b,d,f} then, which set presents set A?

jok3333 [9.3K]

Answer:

set A presents {a,c,e}

7 0

3 years ago

Fred completed 10 math problems. This is 40% of the number of math problems he has to do. How many math problems must he do?

wolverine [178]

10 of the math problems is 40%

40/4 = 10%

10/4 = 2.5 questions

10% = 2.5 questions

10% x 10 = 100%

2.5 questions x 10 = 25 questions

25 questions is the answer

4 0

4 years ago

Read 2 more answers