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devlian [24]
3 years ago
13

Answers asap; greatly appreciated

Mathematics
1 answer:
vagabundo [1.1K]3 years ago
6 0
I believe the answer is D
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Jonathan's age is 1/3 Belinda's age now in 12 years Belinda will be m years old write an algebraic expression to represent Brend
vodomira [7]

Answer:

Kindly check explanation

5 years from now, Johnathan will be (5 + 4) = 9 years

Step-by-step explanation:

Let Belinda's age = x

Jonathan's age =1/3 x

In 12 years, Belinda will be m years old :

Belinda's age now = x

Jonathan's age 5 years from now, if m = 36

Belinda's age in 12 years, Belinda's age = m

x + 12 = 36

x = 36 - 12

x = 24 years

Hence Belinda's age now is 24

Jonathan's age now is (1/3) * 12 = 4 years

Hence, 5 years from now, Johnathan will be (5 + 4) = 9 years

5 0
3 years ago
Use the quadratic formula to solve x2 + 2x - 120 = 0. Think about what other method could also be used to solve this equation. a
pshichka [43]

Answer:

x = 10 , -12

Step-by-step explanation:

Solution:-

- The given quadratic equation is to be solved using the quadratic formula. The general form of a quadratic equation is:

                           ax^2 + bx + c =0  

Where, [ a , b and c are constants ]

- The quadratic formula is given as:

                       

                           x = \frac{-b+/-\sqrt{b^2 - 4*a*c} }{2a}

- The given equation is:

                             x^2 + 2x - 120 = 0

Where, a = 1 , b = 2 , c = -120

- Solve using quadratic formula:

                       x = \frac{-2+/-\sqrt{2^2 - 4*1*(-120)} }{2*1}\\\\x = \frac{-2+/-\sqrt{4 + 480} }{2}\\\\x = \frac{-2+/-(22) }{2}\\\\\\x = 10 , -12    

7 0
3 years ago
An engineer is designing a large steel pad to be installed on the deck of an aircraft carrier. Its total volume will be 18 yd^3.
Shtirlitz [24]

Answer:

The cost of the material for the full-sized pad is;

d) 222,750.00

Step-by-step explanation:

The parameters of the steel pad and the scale model are;

The volume of the deck = 18 yd³

The dimensions of the model of the same material = 6 feet by 4.5 feet and 4.5 inches thick

The weight of the sample, m₂ = 75 lbs

The cost of the steel, P = $55/lb

The dimensions of the sample in yards are;

6 feet = 2 yards, 4.5 feet = 1.5 yards, and 4 inches = 0.\overline 1 yards

The volume of the sample, V₂ = 2 yd. × 1.5 yd. × 0.\overline 1 yd. =  (1/3) yd.³

The density of the sample material, ρ = m₂/V₂

∴ The density of the sample material, ρ = 75 lbs/((1/3)yd.³) = 225 lbs/yd³

Therefore, the density of the material of the pad, ρ = 225 lbs/yd³

The mass of the steel  pad, m₁ = ρ × V₁

∴ The mass of the steel  pad, m₁ = 225 lbs/yd³ × 18 yd³ = 4,050 lbs

The cost of the material for the full-sized steel pad, C = m₁ × P

∴ C = 4,050 lbs × $55/lb = $222,750

6 0
3 years ago
A student received a coupon for 20% off the total purchase price at a clothing store. Let z be the
Pachacha [2.7K]

Answer:

i don't know

Step-by-step explanation:

mag-aral ka mabuti para maging matalino

4 0
3 years ago
Read 2 more answers
What is the square of 0.81?
uysha [10]

Answer:

0.6561

Step-by-step explanation:

i think i could be wrong if am right brainliest

7 0
2 years ago
Read 2 more answers
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