The slope of the line below is -3 use the coordinates of the labeled point to find a point slope equation

Mathematics

1 answer:

neonofarm [45]3 years ago

6 0

Answer:

y = -3x + 8

Step-by-step explanation:

(5,-7), slope is -3

y - y₁ = m(x - x₁)

y₁ = -7

x₁ = 5

m = -3

y + 7 = -3(x - 5)

y + 7 = -3x + 15

y = -3x + 8

You might be interested in

What is the axis of symmetry of f(x)=-3(x+2)^2+4

saw5 [17]

Answer:

line passes through the vertex

Step-by-step explanation:

f(x)=-3(x+2)^2+4

x=-2 it is the x of the vertex

4 0

3 years ago

-3/5 O -0.6 fill the circle with either = < or > to make it correct

bulgar [2K]

-3/5 is greater than -0.6

8 0

3 years ago

A ball is thrown upward from ground level. Its height h, in feet, above the ground after t seconds is h-48t -16t^2.

Marat540 [252]

Answer:

36 feet.

Step-by-step explanation:

We have been given that a ball is thrown upward from ground level. Its height h, in feet, above the ground after t seconds is $h(t)=-48t -16t^2$ . We are asked to find the maximum height of the ball.

We can see that our given equation is a downward opening parabola, so its maximum height will be the vertex of the parabola.

To find the maximum height of the ball, we need to find y-coordinate of vertex of parabola.

Let us find x-coordinate of parabola using formula $x=-\frac{b}{2a}$ .

$x=-\frac{-48}{2(-16)}$

$x=-\frac{48}{32}$

$x=-\frac{3}{2}$

So, the x-coordinate of the parabola is $-\frac{3}{2}$ . Now, we will substitute $x=-\frac{3}{2}$ in our given equation to find y-coordinate of parabola.