I can't see the table, but you find the total amount that the entire fifth grade made and divide it by six. I would round it to the nearest hundredth.

6 0

3 years ago

Mario is constructing a wall around a rectangular area which will cover a maximum of 60 square feet. The length of the wall will

Feliz [49]

Answer:

$W \le 6$

Step-by-step explanation:

Given

$Area = 60ft^2\ (max)$

$Length = 10ft$

Required

Represent the width as an inequality

First, we represent the area as an inequality.

$Area = 60ft^2\ (max)$

max as used above means less than or equal to.

So, we have:

$Area \le 60$

The area of a rectangle is:

$Area = L * W$

So, we have:

$L * W \le 60$

Substitute 10 for L

$10 * W \le 60$

Divide both sides by 10

$\frac{10 * W}{10} \le \frac{60}{10}$

$W \le \frac{60}{10}$

$W \le 6$

7 0

3 years ago