Answer:
The stock Norman purchased increased in its value by 25%.
Step-by-step explanation:
Original Value of the stock = $ 420
New(Current) value of the stock = $ 525
We have to find the percentage change in the value of stock. The formula to calculate the percentage change is:
Substituting the given values into this formula results in:
A positive value of Percentage Change indicates a growth. This means that the stock Norman purchased increased in its value by 25%.
Answer:
your answer would be C hope it helps
Answer:
x = 13
Step-by-step explanation:
x + 3x = 52
Add all common variables
4x = 52
Divide both sides by 4
x = 13
Answer:
only work if mice are recaptured in the same location using the same trapping methods.
Step-by-step explanation:
According to my research on studies conducted by Biology Professionals, I can say that based on the information provided within the question this will only work if mice are recaptured in the same location using the same trapping methods. Otherwise another method might cause the capture of other species and make the results invalid.
I hope this answered your question. If you have any more questions feel free to ask away at Brainly.
Answer:
Std deviation would change but IQR would not change.
Step-by-step explanation:
Given that after entering the test scores from her Statistics class of 25 students, the instructor calculated some statistics of the scores. Upon checking, she discovered that she had entered the top score as 46, but it should have been 56.
When arranged in ascending order the last entry would be 56 instead of 46.
Hence this would not affect the middle entry or quartiles
i.e. in other words there would not be any change in the Interquartile range and Quartile 1 and Quartile 3 are not changed
But standard error would change. this is because total of all entries now increase by 10, so average would increase by 10/25 = 0.40
This in turn would change the mean deviation x-average for each entry and hence square of deviations. Thus variance would change and also standard deviation.
