Answer:
8,9,11
Step-by-step explanation:
A-1
B-2
C-3
D-4
E-5
F-6
G-7
H-8
I-9
J-10
K-11
L-12
M-13
N-14
O-15
Answer:
The required graph is shown below.
Step-by-step explanation:
Consider the provided equation 
We need to draw the graph of the equation.
Put x=0 in the above equation.
The coordinate is (0,2).
Put y=0 in the given equation.
The coordinate is (
,0).
Now draw the graph by using the above coordinates.
The required graph is shown below.
Answer:
(x+3)( 3x^2 +5)
Step-by-step explanation:
3x^3+9x^2+5x+15
Split into two groups
3x^3+9x^2 +5x+15
Factor 3x^2 out of the first group and 5 out of the second group
3x^2 ( x+3) + 5(x+3)
Factor out x+3
(x+3)( 3x^2 +5)
The work done by the gas when the gas expands will be 567.65 ft-lb.
<h3>What is the work done for an isothermal process?</h3>
The Pressure is inversely proportional to the volume.
Let the initial pressure and initial volume be P₁ and V₁, and the final volume be V₂.
Then the work done by the gas will be
WD = P₁ V₁ ln (V₂ / V₁)
A quantity of the gas with an initial volume of 2 cubic feet and an initial pressure of 700 pounds per square foot.
The gas expands to a volume of 3 cubic feet.
Then the work done by the gas will be
WD = 700 x 2 x ln (3/2)
WD = 1400 x 0.405
WD = 567.65 ft-lb
The work done by the gas when the gas expands will be 567.65 ft-lb.
More about the work done for isothermal process link is given below.
brainly.com/question/4218306
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