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3 years ago

13

Can someone please help me on this ty!!

1 answer:

12345 [234]3 years ago

3 0

Answer: There were 624 girls at the football game.

Step-by-step explanation:

Take 1560 divide it by 20 and then multiply it by 8. You are welcome :)

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Luke is swimming in a river with a current flowing west to east at a constant speed of 3.5 meters/second. Assume that Luke's wat

Nitella [24]

Decompose each velocity in its i and j - coordinates.

1) River's velocity

3.5 m/s, west fo east = 3.5i + 0j

2) Luke's velocity

5m/s, 60° east of north

5* sin(60°) i + 5*cos(60°) j = 4.33 i + 2.5 j

3) Resultant velocity

[3.5i + 0j] + [4.33i + 2.5j] = 7.83i + 2.5j

resultant speed = √[ (7.83)^2 + (2.5)^2 ] = 8.22 m/s

angle = arctan(2.5 / 7.83) = 17.7° north of east (equal to 72.3° east of north).

6 0

3 years ago

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Which relation is also a function? A, B, C, or D?

andrew-mc [135]

Answer:

AorD

srry if im wrong its not B because some of them are not compatible

Step-by-step explanation:

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2 years ago

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adoni [48]

Step-by-step explanation:

CCTV cameras in a bit more of the day I will have a great time and where is the only thing that has to do with it

7 0

2 years ago

What is 6 : 8 = n : 12

bonufazy [111]

Answer:

6/8 = n/12

Step-by-step explanation:

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2 years ago

A series of three? separate, adjacent tunnels is constructed through a mountain. Its length is approximately 25 kilometers. Each

Nadya [2.5K]

Answer:

$312.5\pi \text{ km}^3\approx 981.75\text{ km}^3$

Step-by-step explanation:

We have been given that a series of 3 separate, adjacent tunnels is constructed through a mountain. Its length is approximately 25 kilometers.

Each of the three tunnels is shaped like a half-cylinder with a radius of 5 meters.

Since we know that volume of a semicircular or a half cylinder is half the volume of a circular cylinder.

$\text{Volume of a semicircular cylinder}=\frac{\pi r^2h}{2}$ , where,

r = Radius of cylinder,

h = height of the cylinder.

Upon substituting our given values in volume formula we will get,

$\text{Volume of a semicircular cylinder}=\frac{\pi (5\text{ km})^2*25\text{ km}}{2}$

$\text{Volume of a semicircular cylinder}=\frac{\pi*25\text{ km}^2*25\text{ km}}{2}$

$\text{Volume of a semicircular cylinder}=\frac{\pi*625\text{ km}^3}{2}$

$\text{Volume of a semicircular cylinder}=\pi*312.5\text{ km}^3$

$\text{Volume of a semicircular cylinder}=\pi*312.5\text{ km}^3$

$\text{Volume of a semicircular cylinder}=981.74770\text{ km}^3$

Therefore, the volume of earth removed to build the three tunnels is $312.5\pi \text{ km}^3\approx 981.75\text{ km}^3$ .

4 0

2 years ago