Answer:
10
x + y = 5
Step-by-step explanation:
Using the formula, write in standard form.
Vertical line is x=something
we see
(x,y)
(-2,3)
x=-2 is the equation
Answer:
{a , c}
Step-by-step explanation:
first find u intersection p
n(U n P ) = {a , b , c , d} n {b , d , e}
={d , b}
intersection means element or values which lies in both the sets
now to find p complement
note : p( bar at the top ) is read as p complement
p complement = n(U) - n(U n P)
={a , b , c , d} - {d , b}
={a , c}
n(U) -n(U n P) means the elements which is only in n(U ) but not in n(U n P)
I think i’m not really good at math so..
D.
(7,-3) and (4,0)
Answer:
0.1 = 10% probability that the class length is between 51.5 and 51.7 min, that is, P(51.5 < X < 51.7) = 0.1.
Step-by-step explanation:
A distribution is called uniform if each outcome has the same probability of happening.
The uniform distributon has two bounds, a and b, and the probability of finding a value between c and d is given by:

The lengths of a professor's classes has a continuous uniform distribution between 50.0 min and 52.0 min.
This means that 
If one such class is randomly selected, find the probability that the class length is between 51.5 and 51.7 min.

0.1 = 10% probability that the class length is between 51.5 and 51.7 min, that is, P(51.5 < X < 51.7) = 0.1.