Sinx/1+cosx = cscx-cotx prove ls=rs

1 answer:

7 0

L S = sin x/( 1 + cos x) * ( 1 - cos x ) / ( 1 - cos x ) =
= sin x ( 1 - cos x ) / ( 1 - cos² x ) =
= ( sin x - sin x cos x ) / sin² x =
= sin x / sin² x - ( sin x cos x ) / sin² x =
= 1 / sin x - cos x / sin x = csc x - cot x = RS
Therefore: LS = RS

You might be interested in

What is the square root of 18 rounded to the nearest tenth

ratelena [41]

Answer: 4.2

Step-by-step explanation:

when you square root 18 you get 4.242. When rounded to the nearest tenth you get 4.2 since 4 is not nor is 5 and exceeds it.

8 0

3 years ago

Read 2 more answers

How many outer atoms and lone pairs are present in a molecule with a square pyramidal shape?

arlik [135]

Answer:

5 Outer and 1 lone pair

Step-by-step explanation:

A square pyramidal shape results when one of the bonds of an octahedron structure is occupied by a lone pair.

Hence there are 5 bonded atoms and one lone pair. The hybridization about the central atom is $sp^{3} d^2$ .

One of the most common example is Xenon tetraflouride. $XeF_4$ . Looking at its structure we can see that it has 5 pairs of outer atoms and one lone pair. With its coordination number 5. The shape of the orbitals is octahedral.