They are both the same equations, the procedure to obtain x value will be equivalent.
That is the final answer to this question
42765
Let after n week both tanks have same quantity of water .
for first tank
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tank hold 540 gallon of water ,
leaking of water 4 gallon /week
so, in n week water leak from the tank =4× n = 4n
now, after n week quantity of water in the tank = 540 -4n
for second tank
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quantity of water in the tank =720 gallon
leaking of water at the rate = 7gallon/week
so, after n week water leak from the tank = 7× n =7n
after n week quantity of water rest in the tank = 720 -7n
now ,
according to question ,
water in first tank = water in second tank
540 -4n = 720 -7n
7n -4n = 720 -540
3n = 180
n = 60
hence , after 60 week both tank have same quantity of water.
Answer:
x=1, x=8
Step-by-step explanation:
4x2−36x+32=0
Step 1: Factor left side of equation.
4(x−1)(x−8)=0
Step 2: Set factors equal to 0.
x−1=0 or x−8=0
(+1) (+8)
x=1 or x=8
First we are going to find divided by 100 and multiply 20 is equal to four.
We are gonna use x to represent this number.
x/100 * 20 = 4
Solve for x
Therefore x = 20cm
Now that we found x the side of the larger square we are gonna find the area which is side^2.
20 * 20
Therefore the area of the larger square is 400cm^2
