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jasenka [17]
3 years ago
12

- (4x4- 2x' +7x²+2 x - 1)=(x+3)

Mathematics
1 answer:
Gnom [1K]3 years ago
4 0

Answer:

No solution?

Step-by-step explanation:

Im confused, can you give more information.

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For a school project, Sarah plans to build a scale model of an Egyptian pyramid. She will be using a scale of: 1 cm = 5 meters.
Vinvika [58]

Answer:

B

Step-by-step explanation:

you divide 140 by 5 so 28 is the answer

3 0
3 years ago
Read 2 more answers
Help me out :O What is the volume of three cubes, each with a side length of fraction 1 over 3 foot? V = s3, where s is the side
Readme [11.4K]

Answer:

Step-by-step explanation:

s = \frac{1}{3}ft\\

Volume of a cube  =  s³ ft³

Volume of 3 cubes = 3 * s³

                               = 3 * \frac{1}{3} * \frac{1}{3} *\frac{1}{3}\\\\= \frac{1}{3} *\frac{1}{3}\\\\=\frac{1}{3*3}\\\\=\frac{1}{9} ft^{3}

4 0
3 years ago
1500 customers hold a VISA card; 500 hold an American Express card; and, 75 hold a VISA and an American Express. What is the pro
alex41 [277]

Answer:

There is 15% probability that a customer chosen at random holds a VISA card, given that the customer has an American Express card.

P(VISA \:| \:AE) = 15\%\\

Step-by-step explanation:

Number of customers having a Visa card = 1,500

Number of customers having an American Express card = 500

Number of customers having Visa and American Express card = 75

Total number of customers = 1,500 + 500 = 2,000

We are asked to find the probability that a customer chosen at random holds a VISA card, given that the customer has an American Express card.

This problem is related to conditional probability which is given by

P(A \:| \:B) = \frac{P(A \:and \:B)}{P(B)}

For the given problem it becomes

P(VISA \:| \:AE) = \frac{P(VISA \:and \:AE)}{P(AE)}

The probability P(VISA and AE) is given by

P(VISA and AE) = 75/2000

P(VISA and AE) = 0.0375

The probability P(AE) is given by

P(AE) = 500/2000

P(AE) = 0.25

Finally,

P(VISA \:| \:AE) = \frac{P(VISA \:and \:AE)}{P(AE)}\\\\P(VISA \:| \:AE) = \frac{0.0375}{0.25}\\\\P(VISA \:| \:AE) = 0.15\\\\P(VISA \:| \:AE) = 15\%\\

Therefore, there is 15% probability that a customer chosen at random holds a VISA card, given that the customer has an American Express card.

8 0
3 years ago
Does anybody know the answer to those two questions
Anna11 [10]

Answer:

Question Number 2 is 20

Question number 3 is 18x-32

Step-by-step explanation:

7 0
3 years ago
What is the y-intercept<br> of this line?<br> please help asap
mixer [17]

Answer: 9 because of the (0,9)

Step-by-step explanation:

8 0
3 years ago
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