All categories

3 years ago

How does the word equidistant relate to the term perpendicular bisector?

1 answer:

6 0

A perpendicular bisector cuts a line segment directly in half. a property of perpendicular bisectors is that any point on the line of the bisector will be equidistant (the same distance from) both end points.

Ex, If point X was 5 ft away from one endpoint, it would be 5 feet away from the other as well.

You might be interested in

Choose the correct simplification of the expression a6b3/a4b2

Law Incorporation [45]

Answer:

a2b

Step-by-step explanation:

a6b3 / a4b2

When dividing exponents, you subtract them.

a6-4

b3-2

Leaving you with a2b

8 0

3 years ago

The line having an x intercept of 3 and y intercept of 10<br> Write this in Standard form Ax+By=C

Svetlanka [38]

Answer:

The standard form of the line is 10x + 3y = 10

Step-by-step explanation:

First we need to find the slope of the equation, which we can do using the slope equation and the two points given: (3, 0) and (0, 10)

m(slope) = (y2 - y1)/(x2 - x1)

m = (10 - 0)/(0 -3)

m = 10/-3

Now we can write the equation in slope intercept form since we have the slope and the intercept.

y = mx + b

y = -10/3x + 10

Now we can manipulate the equation to get the standard form.

y = -10/3x + 10

10/3x + y = 10

10x + 3y = 30

5 0

3 years ago

Hellllppppppppppp!!!! Please

ella [17]

Answer:

UMMM UMMM UMMM

Step-by-step explanation:

THE ANSWER IS...................THE ANSWER THE NEXT PERSON SAY

7 0

3 years ago

Shannon bought 518 pounds of apples. Bill bought 278pounds of apples. Which most closely estimates how many more pounds of apple

Aleksandr-060686 [28]

Answer:

240 pounds.

Step-by-step explanation:

Given that,

Shannon bought 518 pounds of apples.

Bill bought 278 pounds of apples.

We need to find how many more pounds of apples Shannon bought than Bill.

More Apples = Shannon Apples - Bill Apples

= 518 - 278

= 240

Hence, 240 pounds of apples Shannon bought than Bill.

3 0

3 years ago

For the point P (-17,25) and Q(-10,30), fins the distance d(P,Q) and the coordinates of the midpoint M of the segment PQ.

Nonamiya [84]

Answer:

Distance = 8.6

M = (-13.5,27.5)

Step-by-step explanation:

Distance = $\sqrt{(x_{2 }- x_{1 })^2 + (y_{2 }- y_{1 })^2$

= $\sqrt{(-10_ }- (-17)_{ })^2 + (30_{ }- 25_{ })^2$

= $\sqrt{(-10_{ }+ 17_{ })^2 + 5^2_$

= $\sqrt{7^2+5^2}$

= $\sqrt{49+25}$

= $\sqrt{74}$

= 8.6

Midpoint = $(\frac{x_{2}+x_{1}}{2};\frac{y_{2}+y_{1}}{2})$

= (-10+(-17)) ÷ 2 ; (30+25) ÷ 2

= -27 ÷2 ; 55 ÷ 2

= -13.5, 27.5

3 0

3 years ago