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nexus9112 [7]
3 years ago
8

Help me out in this question please

Mathematics
1 answer:
stira [4]3 years ago
8 0

Answer:

in this 3 is the correct answer

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On the previous problem, you found a unit rate of ounces per box. Explain how you find a unit rate when given a rate.
Dima020 [189]
Divide the numerator and the denominator of the given rate by the denominator of the given rate. so in this case, divide the numerator and denominator of 70/5 by 5 to get 14/1 or 14 students per class
4 0
3 years ago
Read 2 more answers
Simplify the expression. 3y^3-2[4y-y(y-3)]-[2y(y+1)-3y(y^2-1)]
Sever21 [200]

Answer: 6y^(3) - 19y

Step-by-step explanation:

5 0
3 years ago
Ten people from a local youth group went to black hills whitewater rafting tour company for a one day rafting trip. the group pa
ICE Princess25 [194]

42.5p=c

You get you get the number 42.5 since you know 10 people paid 425, you would divide 425 by 10 to know how much every person paid.

M is representing the amount of money each person paid

(M)10=425
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M=42.50 <- since it’s about money

Each person paid $42.50


The cost for 15 people is $637.50.

42.5p=c
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6 0
3 years ago
Question Help
Oxana [17]
X + y = 23000

x.08 + y.09 = 2040

x = 23000 - y

(23000 - y) .08 + y.09 = 2040

1840 - .08y + .09y = 2040

Simplify

.01y = 200

Simplify

Y = 20000

X + 20000 = 23000

X = 3000

CHECK: .08x + .09(20000) = 2040

.08x + 1800 = 2040

Simply .08x = 240

X = 3000
7 0
3 years ago
I need help , I don’t understand this
marta [7]
#2. First, we factor each polynomial. Then, if any terms on both the top and the bottom of the fraction match, they cancel out. So... we do just that. You end up with:

\frac{x(x-4)}{(x+9)(x-4)}

Notice there's an (x-4) on both top and bottom. So they cancel out. That leaves us with your answer of \frac{x}{(x+9)}

#3. We do the same thing as above then multiply and simplify. In the interest of space, I'll cut straight to some simplification. 

\frac{2(x+2)^{3} }{6x(x+2)} ( \frac{5}{(x-2)^{2} } )

Now we start cancelling. For the first fraction, there are 3 (x+2)'s on top and 1 on the bottom so we will cancel out the one on the bottom and leave 2 (x+2)'s on top. There are no more polynomials to cancel out so now we multiply across:

\frac{10(x+2)^{2} }{6x(x-2)^{2} }

10 and 6 share a GCF of 2 so we divide both of those by 2. This leaves us with the final answer of:

\frac{5(x+2)^{2} }{3x(x-2)^{2} }

#4. This equation introduces division and because of it, we must flip the second fraction to make the division sign into a multiplication symbol. Again for space, I'll flip the fraction and simplify in one step. 

\frac{3(x+2)(x-2)}{(x+4)(x-2)} ( \frac{x+4}{6(x+3)})

Now we do our cancelling. First fraction has (x - 2) in the top and bottom. They're gone. The first fraction has a (x + 4) on the bottom and the second fraction has one on the top. Those will also cancel. This leaves you with:

\frac{3(x+2)}{6(x+3)}

3 and 6 share a GCF of 3 so we divide both numbers by this. This leaves you with your final answer:

\frac{x+2}{2(x+3)}

#5. We are adding so we first factor both fractions and see what we need to multiply by to make the denominators the same. I'll do the former first. (10 - x) and (x - 10) are not the same so we multiply the first equation (top and bottom) by (x - 10) and the second equation by (10 - x). Because they will now have the same denominator we can combine them already. This gives us:

\frac{(3+2x)(x-10)+(13+x)(10-x)}{(10-x)(x-10)}

Now we FOIL each to expand and then simplify by combining like terms. Again for space, I'm just showing the result of this; you end up with:

\frac{x^{2}-20x+100}{(10-x)(x-10)}

Now we factor the top. This gives you 2 (x - 10)'s on top and one on bottom. So we just leave one on the top and cancel the bottom one out. This leaves you with your answer:

\frac{x+10}{10-x}

#6. Same process for this one so I won't repeat. I'll just show the work.

\frac{3}{(x-3)(x+2)} +  \frac{2}{(x-3)(x-2)} becomes

\frac{3(x-2) + 2(x+2)}{(x-3)(x+2)(x-2)} which equals

\frac{3x - 6 + 2x + 4}{(x-3)(x+2)(x-2)} giving you the final answer

\frac{5x - 2}{(x-3)(x+2)(x-2)}

#7. For this question we find the least common denominator to make the denominators match. For 5, x, and 2x, the LCD is 10x. So we multiply top and bottom of each fraction by what would make the bottom equal 10x. This rewrites the fraction as:

\frac{3x}{5} ( \frac{2x}{2x}) * ( \frac{5}{x}( \frac{10}{10}) -  \frac{5}{2x} ( \frac{5}{5}))

Simplify to get:

\frac{3x}{5}  * ( \frac{25}{10x})

After simplifying again, you end up with your final answer: 

\frac{3}{2}




8 0
3 years ago
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