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nasty-shy [4]
3 years ago
10

Write the equation of this line in Slope-intercept form,

Mathematics
1 answer:
Shkiper50 [21]3 years ago
8 0

For slope intercept form, you need to identify the slope and y-int of the graph.

y=mx+b, where m=the slope and b=the y-int

The y-int is (0,5), because it's at this point where the line crosses the y-axis. To find the slope, look at rise over run. Immediately you know that the slope is going to be negative because the line slopes down. The slope is -2/1, or just -2, because from one point to the other, the line goes down two points and to the right one point.

So, if m=-2 and b=5, you can set up the equation as y= -2x+5

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Help plzz I need the length of "b" and the answers and the steps to find that answer??? Plz help don't have a lot of time to sub
nadezda [96]

Answer:

Use pythagorean theorem.

Step-by-step explanation:

The length of the shorter sides are 1 & 4

1^2+4^2=c^2

1+16=c^2

17=c^2

So, the length, rounded to the nearest whole inch, would be 4.

To find the perimeter, you need to find the side lengths first.

The short sides are 6 & 7.

6^2+7^2=c^2

36+49=c^2

85=c^2

So the length for that would be 8, in the nearest whole number.

Add all of the side lengths together.

6+7+8= 21

The perimeter is 21.

8 0
3 years ago
Solve R=M + B, for B.
musickatia [10]

Answer:

B = R - M

Step-by-step explanation:

1. R = M + B       Subtract M

2.  R - M = B

8 0
3 years ago
I need help ASAP! Can anyone please check my work?
STALIN [3.7K]

A = event the person got the class they wanted

B = event the person is on the honor roll

P(A) = (number who got the class they wanted)/(number total)

P(A) = 379/500

P(A) = 0.758

There's a 75.8% chance someone will get the class they want

Let's see if being on the honor roll changes the probability we just found

So we want to compute P(A | B). If it is equal to P(A), then being on the honor roll does not change P(A).

---------------

A and B = someone got the class they want and they're on the honor roll

P(A and B) = 64/500

P(A and B) = 0.128

P(B) = 144/500

P(B) = 0.288

P(A | B) = P(A and B)/P(B)

P(A | B) = 0.128/0.288

P(A | B) = 0.44 approximately

This is what you have shown in your steps. This means if we know the person is on the honor roll, then they have a 44% chance of getting the class they want.

Those on the honor roll are at a disadvantage to getting their requested class. Perhaps the thinking is that the honor roll students can handle harder or less popular teachers.

Regardless of motivations, being on the honor roll changes the probability of getting the class you want. So Alex is correct in thinking the honor roll students have a disadvantage. Everything would be fair if P(A | B) = P(A) showing that events A and B are independent. That is not the case here so the events are linked somehow.

8 0
3 years ago
A drink is made by mixing 650 ml of water with 150 ml of fruit juice.
Luda [366]
<h2>○=> <u>Correct answer</u> :</h2>

\boxed{\color{hotpink}\tt18.75\%} of the drink is fruit juice

<h3>○=> <u>Steps to derive correct answer</u> :</h3>

Quantity of water in a drink = 650 ml

Quantity of fruit juice in a drink = 150 ml

Total quantity of both items in the drink :

=\tt 650 + 150

\color{plum}=\tt 800 \: ml

Thus, the total quantity of both items in the drink = 800 ml

Let the percentage of of fruit juice in the drink be x%.

Which means :

=  \tt\frac{x}{100}  \times 800 = 150

= \tt \frac{x \times 800}{100}  = 150

=\tt  \frac{800x}{100}  = 150

=\tt 8x = 150

=\tt x =  \frac{150}{8}

\hookrightarrow\color{plum} \bold{x = 18.75\%}

Then, the percentage of water in the drink :

= \tt100 - 18.75

\color{plum}= \tt81.25\%

Thus, the percentage of water in the drink = 81.25%

<h3>○=> <u>Therefore</u> :</h3>

▪︎Percentage of fruit juice in the drink = 18.75%

▪︎Percentage of water in the drink = 81.75%

8 0
3 years ago
Read 2 more answers
Which of the following is the solution of the following inequality?
Brums [2.3K]

Answer:

x = 3

Step-by-step explanation:

4 + 12.5 > 11x - 3.5 - 2x

16.5 = 5.5x

16.5/5.5 = x

5 0
3 years ago
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