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ladessa [460]
3 years ago
9

Explain how to graph (-3, 4) on a coordinate plane

Mathematics
1 answer:
Svet_ta [14]3 years ago
4 0

Hello!

Explanation:

Origin is a point of intersection of the two axes.

Quadrant is a quarter of the coordinate plane.

(-3,4) should be found in <em><u>quadrant 2.</u></em>

First, you go the left to see negative 3.

Then go up to positive 4.

Hope this helps!

Thanks!

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URGENT!
serg [7]

Answer:

number one is the appropriate answer for this question

7 0
3 years ago
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Ann had 45 fliers to post around town. Last week, she posted 2/3 of them. She posted 1/3 of the remaining fliers. How many flier
Bess [88]

Answer:

48

Step-by-step explanation:

(1/4)16 = 4

48-32-4 = 12 still not posted

checking

32 + 4 + 12 = 48 CHECKS!

7 0
2 years ago
Read 2 more answers
This is due today i would appreciate it a lot if smn could help me with it :/
Vesnalui [34]

Answer:

Conclusion:

The rate of change of function 1  = 3

The rate of change of function 2 = 5/3

  • Hence, function 1 has a greater rate of change

The initial Value of function 1 = y = 2

The initial Value of function 2 = y = 3

  • Hence, function 2 has a greater initial value.

Step-by-step explanation:

Function 1)

Determining rate of change for function 1:

x        1         2         3         4

y       5        8          11        14

Finding the rate of change or slope using the formula

Rate of change = m = [y₂-y₁] / [x₂-x₁]

Taking any two points, let say (1, 5) and (2, 8)

Rate of change = m = [8-5] / [2-1]

                                 = 3/1

                                  = 3

Therefor, the rate of change of function 1 = m = 3

using point-slope form to determine the function equation

y-y₁ = m (x-x₁)

where m is the rate of change or slope

substititng m = 3 and the point (1, 5)

y - 5 = 3(x - 1)

y - 5 = 3x-3

y = 3x-3+5

y = 3x + 2

Thus, equation of function 1 will be:

y = 3x + 2

Determining Initial Value for Function 1:

substituting x = 0 in the equation to determine the initial value

y = 3(0)+2

y = 0+2

y = 2

Therefore, the initial Value of function 1 will be: y = 2

Function 2)

Determining the rate of change for function 2:

Given the function 2

y\:=\:\frac{5}{3}x+3

comparing with the slope-intercept form of a linear function

y = mx+b     where m is the rate of change

so the rate of change of function 2 = m = 5/3

Determining Initial Value for Function 2:

substituting x = 0 in the equation to determine the initial value

y\:=\:\frac{5}{3}x+3

y\:=\:\frac{5}{3}\left(0\right)+3

y = 0+3

y = 3

Therefore, the initial Value of function 2 will be: y = 3

Conclusion:

The rate of change of function 1  = 3

The rate of change of function 2 = 5/3

  • Hence, function 1 has a greater rate of change

The initial Value of function 1 = y = 2

The initial Value of function 2 = y = 3

  • Hence, function 2 has a greater initial value.

8 0
2 years ago
Solve for x. ​ −1.9=x/0.5 ​
Feliz [49]

-1.9 = x/.5  given equation

multiply both sides by .5

.5(-1.9) = x/(.5) *(.5)

-.95 = x



check: -1.9 = -.95/ .5


4 0
3 years ago
Which answer represents the series in sigma notation? −3+(−1)+1+3+5 A:∑j=15(2j−5)
insens350 [35]

Answer:

A:∑j=15(2j−5)

Step-by-step explanation:

a = -3

d = -1 - (-3) = -1 + 3 = 2

j-th term: a + (j-1)d

-3 + (j - 1)(2)

-3 + 2j - 2

2j - 5

8 0
3 years ago
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