3/4's obviously because the percentage is bigger.
<u>We are given the equation:</u>
(a + b)! = a! + b!
<u>Testing the given equation</u>
In order to test it, we will let: a = 2 and b = 3
So, we can rewrite the equation as:
(2+3)! = 2! + 3!
5! = 2! + 3!
<em>We know that (5! = 120) , (2! = 2) and (3! = 6):</em>
120 = 2 + 6
We can see that LHS ≠ RHS,
So, we can say that the given equation is incorrect
The answer is
0.000568902892652.
Using squares of integers numbers, it is found that the solution of the equation is located between the integers x = 1 and x = 2.
The equation given is:

The solution of the equation given is:

The squares of the integers numbers until the square root of 3 are:


Since
, the square root of 3, which is the solution to the equation, is located between the integers x = 1 and x = 2.
A similar problem is given at brainly.com/question/3729492