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Kruka [31]
3 years ago
13

An accelerated life test on a large number of type-D alkaline batteries revealed that the mean life for a particular use before

they failed is 19.0 hours. The distribution of the lives approximated a normal distribution. The standard deviation of the distribution was 1.2 hours. About 95.44 percent of the batteries failed between what two values?a. 8.9 and 18.9
b. 12.2 and 14.2
c. 14.1 and 22.1
d. 16.6 and 21.4
Mathematics
1 answer:
joja [24]3 years ago
8 0

Answer:

option (d) 16.6 and 21.4

Step-by-step explanation:

Data provided in the question:

The mean life for a particular use before they failed = 19.0 hours

The distribution of the lives approximated a normal distribution

The standard deviation of the distribution = 1.2 hours

To find:

The values between which 95.44 percent of the batteries failed

Now,

In Normal distribution, the approximately 95% ( ≈ 95.44% of all values ) falls within 2 standard deviations of the mean

Therefore,

Upper limit = Mean + 2 × standard deviation

⇒ Upper limit = 19.0 + 2 × 1.2 = 21.4

Lower  limit = Mean - 2 × standard deviation

⇒ Lower  limit = 19 - 2 × 1.2 = 16.6

Hence,

the answer is option (d) 16.6 and 21.4

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luda_lava [24]
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8 0
3 years ago
Please help and add steps!!
Veseljchak [2.6K]

Answer:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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7 0
3 years ago
How many grams of 0.5% hydrocortisone cream must be mixed with 180 g of 2.5 % cream to make a 1 % w/w hydrocortisone cream? HINT
Sophie [7]

Answer:

We need 540 grams of 0.5% hydrocortisone cream

Step-by-step explanation:

Lets call x the amount of grams needed. This means that the combined cream will have 180+x grams. We want x such that

x * 0.005 + 180*0.025 = (180+x)*0.01

Hence

0.005x + 4.5 = 1,8+0.01x

Lets put the x in the same side and take common factor

4.5-1.8 = 0.01x-0.005x

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As a result

x = 2.7*0.005 = 540

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