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miss Akunina [59]
3 years ago
11

What are the first 20 positive integers?

Mathematics
2 answers:
ankoles [38]3 years ago
8 0

Answer:0-20

Step-by-step explanation:0 can't be negative

boyakko [2]3 years ago
7 0

Answer:

20*(20+1)/2 = 210

Step-by-step explanation:

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The width of a rectangle is 12 less than twice the length, and the area of the rectangle is 270m2.
NikAS [45]

Answer:

5

Step-by-step explanation:


8 0
3 years ago
Find the value of x in terms of a
Tatiana [17]

Answers:

a= 5x±\sqrt{25x^{2} +24u^{2} \\

 ------------------------------

                6  

u=± \sqrt{2a(3z-5x}

  -------------------------

                2

<h2>Brainliest please!!!! It took me a while to figure this out!</h2>
7 0
3 years ago
The table shows the monthly rainfall at a measuring station. What is the mean monthly rainfall? Round your answer to the nearest
Artyom0805 [142]

Answer:

3.245

Step-by-step explanation:

2.22+1.51+1.86+2.06+3.48+4.57+3.27+5.40+5.45+4.34+2.64+2.14 then divide by twelve because that is the number of months :))))

8 0
2 years ago
Read 2 more answers
Step by step explanation please. i want to try to understand it.
zhenek [66]

Answer:

V_{composite\: figure} =678.24\: in^3

Step-by-step explanation:

  • For a single cylinder:

  • radius (r) = 3 in (Given)

  • height (h) = 8 in (Given)

  • It is given that: all the three cylinders are identical, means their radii and heights are equal.

  • Thus, the volume of composite figure will be equal to three times the volume of single cylinder.

  • \implies V_{composite\: figure} =3(\pi r^2 h)

  • \implies V_{composite\: figure} =3(3.14\times  (3)^2 \times 8)

  • \implies V_{composite\: figure} =3(226.08)

  • \implies V_{composite\: figure} =678.24\: in^3
3 0
2 years ago
Read 2 more answers
The safe load, L, of a wooden beam supported at both ends varies jointly as the width, w, and the square of the depth, d, and in
MakcuM [25]

Answer:

joint variation means L (safe load) is directly proportional to both w and d2

inverse proportionality means L = k/l

So the equation is:

L = k(wd2/l)

You are given:

w = 6 in

d = 5 in

l = 12 ft

L = 7666 lbs

7666 = k(6*52/12)

Solve for the constant, k.

7666 = k (6*25/12)

7666 = k (150/12)

7666 = k (12.5)

613.28 lbs/(ft.in3) = k

Use this k-value to solve for L in the last part of the question.

What safe load, L would a beam 3 in. wide, 7 in. deep and 15 ft long of the same material support? (Round off your answer to the nearest pound.)

w = 3 in

d =7 in

l = 15 ft

k = 613.28 lbs/(ft.in3)

Final Safe load = 6010.144 lbs *** Edited for clarity and to fix a multiplication erro

5 0
1 year ago
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