Answer:
In this case we use the Poisson distribution because we are talking about the occurrence of an event (number of tracks) over a specified interval (in this case an area interval).
The probability of the event occurring x times over an interval is:
P(x) = nˣ × e⁻ⁿ ÷ x!
where n is the mean.
a) P(7) = 6⁷ × e⁻⁶ ÷ 7! = 0.1376
b) P(x ≥ 3) = 1 - P(x < 3) = 1 - P(2) - P(1) - P(0)
P(2) = 6² × e⁻⁶ ÷ 2! = 0.0446
P(1) = 6¹ × e⁻⁶ ÷ 1! = 0.0149
P(0) = 6⁰ × e⁻⁶ ÷ 0! = 0.0025
P(x ≥ 3) = 0.9380
c) P(2 < x < 7) = P(3) + P(4) + P(5) + P(6) = 0.0892 + 0.1339 + 0.1606 + 0.1606 = 0.5443
d) The mean is going to be 6.
e) The standard deviation is √n = √6 = 2.4
You add 1 to the numerator each time
Answer:
Vertical stretch of factor of 3
translated to the right 2
translated up 5
Step-by-step explanation:
(6/5.55) * 100 = 108.11 %
The percent error is 108.11 %
