Answer:
25.6 units
Step-by-step explanation:
From the figure we can infer that our triangle has vertices A = (-5, 4), B = (1, 4), and C = (3, -4).
First thing we are doing is find the lengths of AB, BC, and AC using the distance formula:
where
are the coordinates of the first point
are the coordinates of the second point
- For AB:
![d=\sqrt{[1-(-5)]^{2}+(4-4)^2}](https://tex.z-dn.net/?f=d%3D%5Csqrt%7B%5B1-%28-5%29%5D%5E%7B2%7D%2B%284-4%29%5E2%7D)
- For BC:
- For AC:
![d=\sqrt{[3-(-5)]^{2} +(-4-4)^{2}}](https://tex.z-dn.net/?f=d%3D%5Csqrt%7B%5B3-%28-5%29%5D%5E%7B2%7D%20%2B%28-4-4%29%5E%7B2%7D%7D)
Next, now that we have our lengths, we can add them to find the perimeter of our triangle:
We can conclude that the perimeter of the triangle shown in the figure is 25.6 units.
Look at it this way:
When you flip a coin, the probability of it landing with EITHER side showing
is 100%.
This leads us to the rule ...
The sum of the probabilities of
all possible outcomes is 100%.
For a coin: (probability of heads) plus (probability of tails) = 100%.
That just says: We're 100% sure that the coin will land with either
heads or tails up.
An "honest" coin gets heads 50% of the time and tails the other 50%.
But if the coin is all bent and squashed and has a feather stuck to
one side and a wad of gum on the other side so that it comes up
heads 70% of the time, then the coin isn't 'honest'. But it still has to
land EITHER heads OR tails, so the sum of the probabilities is still 100%.
So the probability of heads is 30%.
