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kifflom [539]
3 years ago
6

Whats x in this equation 2(×+3)=1

Mathematics
2 answers:
konstantin123 [22]3 years ago
4 0
2x+6=1
-5+6=1
-5÷2=-2.5
x=-2.5
mamaluj [8]3 years ago
3 0
The answer is x = -5/2 and -2.5.

x + 3 = 1/2 ( divide both sides by 2)
x = 1/2 - 3 ( subtract 3 from both sides )
x = -5/2 ( simplify 1/2 - 3 to -5/2 )
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Is the given ordered pair a solution to the equation? <br><br><br> y=2x+7;(-2, 3)
iren2701 [21]

Answer:

The answer to your question is: Yes, it is a solution

Step-by-step explanation:

           

Point  (-2, 3)

                         Line:            y = 2x + 7

Process, replace the point in the line

                                          3 = 2(-2) + 7

                                          3 = -4 + 7

                                          3 = 3

As we got that 3 equals 3, then the point given is a solution of the equation.

               

5 0
4 years ago
Which statement correctly describes the relationship between the graph of f(x)g(x) and g(x)=f(x−7)?
Lelu [443]
G(x) would have to be -->7 units.
The relationship between f(x) and s(x) where s(x)=af(x-b)+z is that g(x) is f(x) stretched by the reciprocal of a, b is the liar (all x values go up if b goes down and visa versa), and it moves up z units. 
4 0
3 years ago
Read 2 more answers
Factor completely. x2−11x+24
Serjik [45]

Step-by-step explanation:

x2-8x-3x+24=0

x(x-8) 3(x+8)

(x-8)(x+8)

x-8=0 or x+8=0

x=8. x= -8

6 0
3 years ago
If 2/7 of the animals at a zoo are birds and 1/8 of the birds are flamingos, what portion of the animals at the zoo are flamingo
alex41 [277]
It says it in the question does it not?
7 0
3 years ago
Read 2 more answers
Dos cuadrados de lado
Kaylis [27]

La franja amarilla del rectángulo tiene un área de 30 centímetros cuadrados.

<h3>¿Cuál es el área de la franja amarilla del rectángulo?</h3>

En este problema tenemos un rectángulo formado por dos cuadrados que se traslapan uno al otro. La franja amarilla es el área en la que los cuadrados se traslapan. La anchura del rectángulo es descrita por la siguiente ecuación:

(10 - x) + 2 · x = 17

Donde x se mide en centímetros.

A continuación, despejamos x en la ecuación descrita:

10 + x = 17

x = 7

Ahora, el área de la franja amarilla se determina mediante la fórmula de area de un rectángulo:

A = b · h

Donde:

  • b - Base del rectángulo, en centímetros.
  • h - Altura del rectángulo, en centímetros.
  • A - Área del rectángulo, en centímetros cuadrados.

A = (10 - 7) · 10

A = 3 · 10

A = 30

El área de la franja amarilla del rectángulo es igual a 30 centímetros cuadrados.

Para aprender más sobre áreas de rectángulos: brainly.com/question/23058403

#SPJ1

8 0
1 year ago
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