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4 years ago

Who was a Mexican american who fought for Texan independence from mexico and later became a Texas senator.

1 answer:

5 0

The answer is Juan Seguin. He was a political and military character of the Texas Revolution serving to establish the independence of Texas. Several places and institutes are named in his integrity, as well as the county seat of Seguin in Guadalupe County, Juan Seguin Monument in Seguin, the Juan N. Seguin Memorial Interchange in Houston, World War II Liberty Ship SS Juan N. Seguin, and Seguin High School in Arlington.

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99 X 99 X 99 / 9 - 99 /99 PLEASE EXPLAIN ;)

charle [14.2K]

Answer:

107810

Step-by-step explanation:

You can use the order of operations! So we start with 99^3/9. That is 99^2*11. So now let’s do 99/99, it’s 1. So 99^2*11 is 107811, so the answer is 107810.

8 0

4 years ago

Read 2 more answers

A tree farming company is testing how many items customers purchase during their visits. Based on many results, the (partial) pr

kkurt [141]

Answer:

X probability = 0.02

Cumulative frequency at x ( 6 ) = 1

Step-by-step explanation:

X P ( X ) Cf ( X )

1 0.58 0.58

2 0.18 0.58 + 0.18 = 0.76

3 0.10 0.76 + 0.10 = 0.86

4 0.07 0.86 + 0.07 = 0.93

5 0.05 0.93 + 0.05 = 0.98

6 0.02 0.98 + 0.02 = 1

4 0

3 years ago

Please help me ASAP!!!!

Ket [755]

ANSWER

$34 {units}^{2}$

EXPLANATION

The width of the rectangle is |AB|

A(-1,4) and B(3,3)

We use the distance formula,

$d = \sqrt{ {(x_2-x_1)}^{2} + {(y_2-y_1)}^{2} }$

This implies that,.

$d = \sqrt{ {(3- - 1)}^{2} + {(3 - 4)}^{2} }$

$d = \sqrt{ {(4)}^{2} + {( - 1)}^{2} }$

$d = \sqrt{ 16+ 1 }$

$d = \sqrt{17}$

The length is BC

C(1,-5) and B(3,3)

$d = \sqrt{ {(3- 1)}^{2} + {(3 - - 5)}^{2} }$

$d = \sqrt{ {2}^{2} + {(8)}^{2} }$

$d = \sqrt{4 + 64 }$

$d = \sqrt{68}$

$d = 2 \sqrt{17}$

The area is

$= l \times w$

$= 2 \sqrt{17} \times \sqrt{17}$

$2 \times 17 = 34 {units}^{2}$

5 0

4 years ago

Need help if someone can show how this is done plz

romanna [79]

Answer:

8.5

Step-by-step explanation:

use pythagorean theorem to find the other side of the tirange.

$a^{2} +b^{2} =c^{2}$

fill in what you know: $15^{2} + 8^{2} = c^{2}$

then solve for c $225 + 64 = c^{2}$ then $289 = c^{2}$ .

then take the square root of both sides because you just want c.

$\sqrt{289} = \sqrt{c^{2} }$ . then you get that c = 17. now, the radius is half of the diameter. the diameter is the segment ab, which we found to = 17, so if the radius if half the diameter, we divide 17 by 2 and we get 8.5. so, the radius of the circle is 8.5.

7 0

3 years ago

In an experiment, the temperature of a sample is measured as 16 degrees Celsius.

Ray Of Light [21]

Answer: T=16 ± 0.12 ° CA Aw

Step-by-step explanation:

4 0

3 years ago