Parallel lines have the same slope.
To compare the slopes of two different lines, you have to get
both equations into the form of
y = 'm' x + (a number) .
In that form, the 'm' is the slope of the line.
Notice that it's the number next to the 'x' .
The equation given in the question is y = 3 - 2 x .
Right away, they've done something to confuse you.
You always expect the 'x' term to be right after the 'equals' sign,
but here, they put it at the end. The slope of this line is the -2 .
Go through the choices, one at a time.
Look for another one with a slope of -2 .
Remember, rearrange the equation to read ' y = everything else ',
and then the slope is the number next to the 'x'.
Choice #4: y = 4x - 2 . The slope is 4 . That's not it.
Choice #3: y = 3 - 4x . The slope is -4 . That's not it.
Choice #2). 2x + 4y = 1
Subtract 2x from each side: 4y = 1 - 2x
Divide each side by 4 : y = 1/4 - 1/2 x .
The slope is -1/2. That's not it.
Choice #1). 4x + 2y = 5
Subtract 4x from each side: 2y = 5 - 4x
Divide each side by 2 : y = 5/2 - 2 x .
The slope is -2 .
This one is it.
This one is parallel to y = 3 - 2x ,
because they have the same slope.
The complete question is
Which statement is true about the factorization of 30x² + 40xy + 51y²<span>?
A. The factorization of the polynomial is 10(3x2 + 4xy + 5y2).
B. The polynomial can be rewritten as the product of a trinomial and xy.
C. The greatest common factor of the polynomial is 51x2y2.
D. The polynomial is prime, and the greatest common factor of the terms is 1.
we know that
case A) </span>is not right because 10 is not a common factor of the three terms.
case B) is not right because the original polynomial is already a trinomial
case C) is not right because the terms do not contain 51x^2y^2
<span>case D) is right
because
</span><span>Factors of 30 are-----> 1,2,3,5,6,10,15,30
</span>Factors of 40 are-----> 1,2,4,5,8,10,20,40
Factors of 51 are-----> 1,51
<span>so
</span><span>The "Greatest Common Factor" is the largest of the common factors
</span><span>the GFC is 1
therefore
the answer is the option
</span>D. The polynomial is prime, and the greatest common factor of the terms is 1<span>
</span>
Answer:
m=2 and n=3
Step-by-step explanation:
<u>Step</u> :-
Given ![[ 2 x^{n}y^{2} ]^m = 4 x^6 y^4](https://tex.z-dn.net/?f=%5B%202%20x%5E%7Bn%7Dy%5E%7B2%7D%20%5D%5Em%20%3D%204%20x%5E6%20y%5E4)
using algebraic formula 
now

now equating 'x' powers, we get

....(1)
now

Equating 'y' powers ,we get
2 m=4
m=2
substitute m= 2 in equation (1)
we get
2 n=6
n=3
verification:-
substitute m=2 and n=3 , we get
![[ 2 x^{n}y^{2} ]^m = 4 x^6 y^4](https://tex.z-dn.net/?f=%5B%202%20x%5E%7Bn%7Dy%5E%7B2%7D%20%5D%5Em%20%3D%204%20x%5E6%20y%5E4)


both are equating so m= 2 and n=3
no solutions → C
The 2 given lines are parallel and never intersect thus no solution