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Answer:
In general the number of bit registers in Intel 80x86 CPU design when combined together forms a 16 - bit register
An example of the -bit registers are AH, AL, BH, BL, CH, CL, DH, and DL
Explanation:
Solution
The 8086 CPU design has a total of eight 8-bit registers and these register can be integrated together to make 16- bit register as well.
The 16-bit data is stored by breaking the data into a low-order byte and high order byte.
The name of the 8 bit registers is shown below:
AH, AL, BH, BL, CH, CL, DH, and DL
We use ideas and thoughts that have already been protected by the law which is called Copyright. We reworking copyright material means we are taking somebody's ideas and calling it ours. Which is not right by the law.
I think select the video insert select the movie option under illustrations resize the video player then select the insert tab i’m not 100 percent sure tho
Answer: 83.17
Explanation:
By definition, the dB is an adimensional unit, used to simplify calculations when numbers are either too big or too small, specially in telecommunications.
It applies specifically to power, and it is defined as follows:
P (dB) = 10 log₁₀ P₁ / P₂
Usually P₂ is a reference, for instance, if P₂ = 1 mW, dB is called as dBm (dB referred to 1 mW), but it is always adimensional.
In our question, we know that we have a numerical ratio, that is expressed in dB as 19.2 dB.
Applying the dB definition, we can write the following:
10 log₁₀ X = 19.2 ⇒ log₁₀ X = 19.2 / 10 = 1.92
Solving the logarithmic equation, we can compute X as follows:
X = 10^1.92 = 83.17
X = 83.17