Question

Gaseous chlorine is held in two separate containers at identical temperature and pressure. The volume of container 1 is 1.30 L, and it contains 6.70 mol of the gas. The volume of container 2 is 2.33 L. How many moles of the gas are in container 2?

Answer 1

Answer : The number of moles of gas are in container 2 are 12.008 moles.

Explanation :

According to the Avogadro's Law, the volume of the gas is directly proportional to the number of moles of the gas at constant pressure and temperature.

$V\propto n$

or,

$\frac{V_1}{V_2}=\frac{n_1}{n_2}$

where,

$V_1$ = initial volume of gas in container 1 = 1.30 L

$V_2$ = final volume of gas in container 1 = 2.33 L

$n_1$ = initial moles of gas in container 2 = 6.70 mole

$n_2$ = final moles of gas in container 2 = ?

Now put all the given values in the above formula, we get the final moles of the gas.

$\frac{1.30L}{2.33L}=\frac{6.70mole}{n_2}$

$n_2=12.008mole$

Therefore, the number of moles of gas are in container 2 are 12.008 moles.