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pochemuha
3 years ago
10

Match each section of the atomic structure

Chemistry
2 answers:
siniylev [52]3 years ago
6 0

Answer:

1e 2a 3d 4c 5d

Explanation:

1) Electrons

These particles spin around the nucleus of the atom, they are negatively charged. They have their orbits.

2) Protons

This another kind of subatomic particle, is located on the nucleus of the atom is positively  charged they constitute the atomic nuclei with the other main particle

3) Neutrons

They do not possess electric charge, all atoms but the Hydrogen have neutrons within. Neutrons and Protons form the Atomic Nuclei.

4) Electron Cloud

Even though, this illustration is transparent maybe a translucid one should be more appropriate. An Electron Cloud depicts an area and the electron is not depicted as a dot. So, again this is not the best picture of an Electron Cloud, the point is since we can't precisely say where the electron passes let's draw areas, instead of lines.

5) Nucleus

The mass of particles at the center whose constituent parts are mainly the protons and neutrons and other subatomic particles, not mentioned here as quarks, bosoms, etc.

Lesechka [4]3 years ago
4 0

<>"Atomic particles. Protons and neutrons are heavier than electrons and reside in the nucleus at the center of the atom. Electrons are extremely lightweight and exist in a cloud orbiting the nucleus. The electron cloud has a radius 10,000 times greater than the nucleus."<>

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If a hard water solution is saturated with calcium carbonate, what volume of the solution has to evaporate to deposit 1.00×102 m
olasank [31]
I think the Ksp for Calcium Carbonate is around 5×10⁻⁹
(I don't know if this is the Ksp value that you use because I read somewhere that this value can vary.  You should probably check with your teacher with what Ksp value they want you to use)

the equation for the dissociation CaCO₃ in water is CaCO₃(s)⇄Ca²⁺(aq)+CO₃²⁻(aq) which means that the concentration of Ca²⁺ is equal to the concentration of CO₃²⁻ in solution.  For every molecule of CaCO₃ that dissolves, one atom of Ca²⁺ and one molecule of CO₃²⁻ is put into solution which is why the concentrations are equal in solution. 

Since Ksp=[Ca²⁺][CO₃²⁻] and we know that [Ca²⁺]=[CO₃²⁻] we can rewrite the equation as Ksp=x² since if you say that [Ca²⁺]=[CO₃²⁻] when you multiply them together you get the concentration squared (I am calling the concentration x for right now).

when solving for x:
5×10⁻⁹=x²
x=0.0000707
Therefore [Ca²⁺]=[CO₃²⁻]=0.0000707mol/L which also shows how much calcium carbonate is dissolved per liter of water since the amount of Ca²⁺ and CO₃²⁻ in solution came from the calcium in a 1 to 1 molar ratio as shown in the equation (the value we found for x is the molar solubility of calcium carbonate).

Using the fact that the molar mass of calcium carbonate is 100.09g/mol you can use dimensional analysis as fallows:
(0.0000707mol/L)(100.09g/mol)=0.007077g/L
That means that there is 0.007077g of Calcium carbonate that can precipitate out of 1L of water.

since the question is asking for how much water needs to be evaporated to precipitate 100mg (0.1g) of Calcium you have to do the fallowing calculation:
(0.1g)/(0.007077g/L)=14.13L of water.
14.13L of water needs to evaporate in order to precipitate out 100mg of calcium carbonate

These types of questions can get long and confusing so I bolded parts that were important to try to guide you through it more easily.

I hope this helps.  Let me know if anything is unclear.
6 0
3 years ago
Please help me out arranging the order from smallest to biggest ions
dmitriy555 [2]
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6 0
3 years ago
Help help help.
Whitepunk [10]
I think B
Hope this helps!
4 0
3 years ago
In a healthy pond, the temperature is 16°C (61°F). What is the most likely pH of this pond?
masha68 [24]

Answer:

A . 6.3 In a healthy pond, the temperature is 16°C (61°F). What is the most likely pH of this pond

7 0
2 years ago
For each reaction, find the value of ΔSo. Report the value with the appropriate sign. (a) 3 NO2(g) + H2O(l) → 2 HNO3(l) + NO(g)
aev [14]

Answer:

ΔS° = -268.13 J/K

Explanation:

Let's consider the following balanced equation.

3 NO₂(g) + H₂O(l) → 2 HNO₃(l) + NO(g)

We can calculate the standard entropy change of a reaction (ΔS°) using the following expression:

ΔS° = ∑np.Sp° - ∑nr.Sr°

where,

ni are the moles of reactants and products

Si are the standard molar entropies of reactants and products

ΔS° = [2 mol × S°(HNO₃(l)) + 1 mol × S°(NO(g))] - [3 mol × S°(NO₂(g)) + 1 mol × S°(H₂O(l))]

ΔS° = [2 mol × 155.6 J/K.mol + 1 mol × 210.76 J/K.mol] - [3 mol × 240.06 J/K.mol + 1 mol × 69.91 J/k.mol]

ΔS° = -268.13 J/K

7 0
3 years ago
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