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3 years ago

Match each section of the atomic structure

Chemistry

2 answers:

siniylev [52]3 years ago

6 0

Answer:

1e 2a 3d 4c 5d

Explanation:

1) Electrons

These particles spin around the nucleus of the atom, they are negatively charged. They have their orbits.

2) Protons

This another kind of subatomic particle, is located on the nucleus of the atom is positively charged they constitute the atomic nuclei with the other main particle

3) Neutrons

They do not possess electric charge, all atoms but the Hydrogen have neutrons within. Neutrons and Protons form the Atomic Nuclei.

4) Electron Cloud

Even though, this illustration is transparent maybe a translucid one should be more appropriate. An Electron Cloud depicts an area and the electron is not depicted as a dot. So, again this is not the best picture of an Electron Cloud, the point is since we can't precisely say where the electron passes let's draw areas, instead of lines.

5) Nucleus

The mass of particles at the center whose constituent parts are mainly the protons and neutrons and other subatomic particles, not mentioned here as quarks, bosoms, etc.

Lesechka [4]3 years ago

4 0

<>"Atomic particles. Protons and neutrons are heavier than electrons and reside in the nucleus at the center of the atom. Electrons are extremely lightweight and exist in a cloud orbiting the nucleus. The electron cloud has a radius 10,000 times greater than the nucleus."<>

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A horizontal cylinder equipped with a frictionless piston contains 785 cm3 of steam at 400 K and 125 kPa pressure. A total of 83

guapka [62]

Answer:

a. 478.69 K

b. 939.43 $cm^{3}$

c. 19.30 J

d. 64.5J

Explanation:

From the question, we can identify the following;

$V_{o}$ = 785 $cm^{3}$ = 0.000785 $m^{3}$

$T_{o}$ = 400K

$P_{o}$ = 125 Kpa = 125 000 Pa

Using the ideal gas equation,

PV = nRT

where R is the molar gas constant = 8.314 $m^{3}$ ⋅Pa⋅ $K^{-1}$ ⋅ $mol^{-1}$

Thus, n = PV/RT = (125000 × 0.000785)/(8.314 × 400) = 0.03 mol

a. Steam temperature in K

To calculate this, we use the constant pressure process;

q = nΔH

Where q is 83.8J according to the question

Thus;

83.8 = 0.03 × [34980 + 35.5 $T_{1}$ - (34980 + 35.5 $T_{o}$ )]

83.8 = (0.03 × 35.5) ( $T_{1}$ - 400K)

83.8 = 1.065 ( $T_{1}$ - 400)

78.69 = ( $T_{1}$ - 400)

$T_{1}$ = 400 + 78.69

$T_{1}$ = 478.69 K

b. Final cylinder volume

To calculate this, we make use of the Charles' law(Temperature and pressure are directly proportional)

$V_{1}$ / $T_{1}$ = $V_{o}$ / $T_{o}$

$V_{1}$ = $V_{o}$ $T_{1}$ / $T_{o}$

$V_{1}$ = (785 × 478.69)/400

$V_{1}$ = 939.43 $cm^{3}$

c. Work done by the system

Mathematically, the work done by the system is calculated as follows;

w = P( $V_{1}$ - $V_{o}$ ) = 125 KPa ( 939.43 - 785) = 19.30 J

d. Change in internal energy of the steam in J

ΔU = q - w = 83.8 - 19.3 = 64.5J

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3 years ago

In the energy diagram, which number represents the potential energy of the products?

Lesechka [4]

I say Answer choice A because it is a straight line and it hasn't gone under all those reactions yet.

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3 years ago

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Which of the following is an example of +ΔS

S_A_V [24]

If +ΔS means an increase in entropy, or disorder, then a solid subliming into a gas would be an increase in disorder.

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3 years ago

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What is the mass in grams of 1.204 x 1024 atoms of carbon?

-Dominant- [34]

Answer:

24g of carbon

Explanation:

From Avogadro's hypothesis, we understood that 1mole of any substance contains 6.02x10^23 atoms. This gives us a background understanding that 1mole of carbon also contains 6.02x10^23 atoms.

1 mole of carbon = 12g

If 12g of carbon contains 6.02x10^23 atoms,

then Xg of carbon will contain 1.204 x 1024 atoms i.e

Xg of carbon = (12x1.204x10^24)/6.02x10^23 = 24g

Therefore, 24g of carbon contains 1.204x10^24 atoms

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3 years ago

A chemist uses 0.25 L of 2.00 M H2SO4 to completely neutralize a 2.00 L of solution of NaOH. The balanced chemical equation of t

Mrac [35]

The balanced equation of NaOH and H2SO4 would be:

2NaOH + H2SO4 = Na2SO4 + 2H2O

To determine the concentration of NaOH, we first find the moles of NaOH used in the reaction. We start with the the concentration and volume of H2SO4. We do as follows:

2.00 M H2SO4 ( 0.25 L ) = 0.5 mol H2SO4

0.5 mol H2SO4 ( 2 mol NaOH / 1 mol H2SO4) = 1 mol NaOH

Molarity = 1 mol NaOH / 2.00 L NaOH solution = 0.5 M NaOH solution

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3 years ago

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