Please provide the following
Well weathering adds different elements to rocks which they might not be used to. For example, very hard rain & harsh winds could push a rock, causing it to fall & break off into smaller rocks.
Answer:
0.1313 g.
Explanation:
- It is known that at STP, 1.0 mole of ideal gas occupies 22.4 L.
- Suppose that hydrogen behaves ideally and at STP conditions.
<u><em>Using cross multiplication:</em></u>
1.0 mol of hydrogen occupies → 22.4 L.
??? mol of hydrogen occupies → 1.47 L.
∴ The no. of moles of hydrogen that occupies 1.47 L = (1.0 mol)(1.47 L)/(22.4 L) = 6.563 x 10⁻² mol.
- Now, we can get the no. of grams of hydrogen in 6.563 x 10⁻² mol:
<em>The no. of grams of hydrogen = no. of hydrogen moles x molar mass of hydrogen</em> = (6.563 x 10⁻² mol)(2.0 g/mol) = <em>0.1313 g.</em>
Answer:
![\Delta G =-103.95kJ](https://tex.z-dn.net/?f=%5CDelta%20G%20%3D-103.95kJ)
Explanation:
Hello there!
In this case, since the thermodynamic definition of the Gibbs free energy for a change process is:
![\Delta G =\Delta H-T\Delta S](https://tex.z-dn.net/?f=%5CDelta%20G%20%3D%5CDelta%20H-T%5CDelta%20S)
It is possible to plug in the given H, T and S with consistent units, to obtain the correct G as shown below:
![\Delta G =-111.4kJ-(298K)(-25.0\frac{J}{K}*\frac{1kJ}{1000J} )\\\\\Delta G =-103.95kJ](https://tex.z-dn.net/?f=%5CDelta%20G%20%3D-111.4kJ-%28298K%29%28-25.0%5Cfrac%7BJ%7D%7BK%7D%2A%5Cfrac%7B1kJ%7D%7B1000J%7D%20%29%5C%5C%5C%5C%5CDelta%20G%20%3D-103.95kJ)
Best regards!
Answer:
Conditioning two or three times will insure that the concentration of titrant is not changed by a stray drop of water.
Explanation:
"Check the tip of the buret for an air bubble. To remove an air bubble, whack the side of the buret tip while solution is flowing".