Answer:
ΔG = - 590.20 kJ/mol
Explanation:
The formula for calculating Gibb's Free Energy can be written as:
ΔG = ΔH - TΔS
Given That:
ΔH = -720.5 kJ/mol
T = 221.0°C = (221.0 + 273.15) = 494.15 K
ΔS° = -263.7 J/K
So; ΔS° = -0.2637 kJ/K if being converted from joule to Kilo-joule
Since we are all set, let replace our given data in the above equation:
ΔG = (-720.5 kJ/mol) - (494.15 K) ( - 0.2637 kJ/K)
ΔG = (-720.5 kJ/mol) - (- 130.30755)
ΔG = -720.5 kJ/mol + 130.30755
ΔG = -590.192645 kJ/mol
ΔG = - 590.20 kJ/mol
Thus, The value of ΔG° at 221.0°C for the formation of phosphorous trichloride from its constituent elements, P2(g) + 3Cl2(g) → 2PCl3(g) is <u>-590.20</u> kJ/mol.
Answer:
B. Changes in energy in systems.
Explanation:
Thermodynamics is a branch of physics which deals with heat and temperature in relation to energy work radiation and characteristics of matter.
This field studies the causes of energy changes and the effects of energy changes to chemical and physical systems.
Answer:
124.56 moles of Hydrogen atoms.
Explanation:
We'll begin by calculating the number of moles of ethane that contains 1.25×10²⁵ molecules. This can be obtained as follow:
From Avogadro's hypothesis, 1 mole of any substance contains 6.02x10²³ molecules. This implies that 1 mole of ethane also contains 6.02x10²³ molecules.
Thus, 6.02x10²³ molecules are present in 1 mole of ethane.
Therefore, 1.25×10²⁵ molecules are present in = 1.25×10²⁵/6.02x10²³ = 20.76
Therefore, 20.76 moles of ethane contains 1.25×10²⁵ molecules.
Finally, we shall determine the number of mole of Hydrogen in 20.76 moles of ethane. This can be obtained as follow:
Ethane has formula as C2H6.
From the formula, 1 mole of ethane, C2H6 contains 6 moles of Hydrogen atoms.
Therefore, 20.76 moles of ethane will contain = 20.76 × 6 = 124.56 moles of Hydrogen atoms.
Therefore, 1.25×10²⁵ molecules of ethane contains 124.56 moles of Hydrogen atoms.
Explanation:
When a chlorine atom forms an ion, it gains electrons, making it negative. A neutral chlorine will become a chlorine with a -1 charge. When it gains an electron, the radius increases.
When a sodium atom forms an ion, it loses electrons, making it positive. A neutral sodium will become a sodium with a +1 charge. When it loses an electron, the radius decreases.
