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Cloud [144]
3 years ago
9

Find the limit of (lnx)³/x as x approaches infinity.

Mathematics
1 answer:
EastWind [94]3 years ago
5 0
Ok, so one way is like your way

so
if we test some numbers
for x=10
we get about 12.3/10≈1.2
for x=100000
we get 1522.03/100000≈0.01522
the top number keeps getting smaller reletive to bottom number
when x=1000000000
we get 8899.68/1000000000≈0.000009

we notice the bottom number is increaseing at a faster rate that the botom one
when x approaches infinity,the bottom number will be so big it will become a fraction that evaluates to basically zero becuase it evaluates to a very small number that is negligible
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The standard deviation of a sample taken from population A is 17.6 for a sample of 25.
lawyer [7]

Answer:

The standard deviation of the sample mean differences is _5.23_

Step-by-step explanation:

We have a sample of a population A and a sample of a population B.

For the sample of population A, the standard deviation \sigma_A is

\sigma_A = 17.6

The sample size n_A is:

n_A = 25.

For the sample of population B, the standard deviation \sigma_B is

\sigma_B = 21.2

The sample size n_B is:

n_B = 30.

Then the standard deviation for the difference of means has the following form:

\sigma=\sqrt{\frac{\sigma_A^2}{n_A}+\frac{\sigma_B^2}{n_B}}

Finally

\sigma=\sqrt{\frac{17.6^2}{25}+\frac{21.2^2}{30}}\\\\\sigma= 5.23

7 0
4 years ago
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valentinak56 [21]

Answer:

-13.53

Step-by-step explanation:

x=-13.53

Hope it helped

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Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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