To answer this
problem, we use the binomial distribution formula for probability:
P (x) = [n!
/ (n-x)! x!] p^x q^(n-x)
Where,
n = the
total number of test questions = 10
<span>x = the
total number of test questions to pass = >6</span>
p =
probability of success = 0.5
q =
probability of failure = 0.5
Given the
formula, let us calculate for the probabilities that the student will get at
least 6 correct questions by guessing.
P (6) = [10!
/ (4)! 6!] (0.5)^6 0.5^(4) = 0.205078
P (7) = [10!
/ (3)! 7!] (0.5)^7 0.5^(3) = 0.117188
P (8) = [10!
/ (2)! 8!] (0.5)^8 0.5^(2) = 0.043945
P (9) = [10!
/ (1)! 9!] (0.5)^9 0.5^(1) = 0.009766
P (10) = [10!
/ (0)! 10!] (0.5)^10 0.5^(0) = 0.000977
Total
Probability = 0.376953 = 0.38 = 38%
<span>There is a
38% chance the student will pass.</span>
Answer:
Step-by-step explanation:
Use the normcdf( function on a basic calculator as follows:
normcdf(-1000, 9750, 12000, 4500). Result: 0.307. This is the area under the standard normal curve to the left of 9750.
But we want the area under the standard normal curve to the right of 9750, so we subtract this 0.307 from 1.000, obtaining the desired result: 0.693. This roughly corresponds with the last of the given possible answers, 69.15%.
Step-by-step explanation:
We have,
Mass of ball is 9 kg
Initial speed, u = 5 m/s
Final speed, v = -2 m/s (negative as it bounces off)
(a) The change in velocity of the bowling ball is :
(b) Change of momentum of the ball is :
|p| = 630 kg-m/s
(c) Impulse momentum theorem states that the change in momentum of the ball is equal to the impulse exerted on the ball. So, impulse is 630 kg-m/s.
(d) Impulse is also given by :
