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kkurt [141]
2 years ago
13

What is a common method for testing a spot weld?

Computers and Technology
1 answer:
Gennadij [26K]2 years ago
4 0
Hey there,
The common method is destructive testing.

Hope this helps :))

<em>~Top♥</em>
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Use pelican, or similar heavy duty cases

Explanation:

Pelican is a brand btw. 10/10 would recommend

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What is one pass of a coding sequence called?​
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In computer programming, a one-pass compiler is a compiler that passes through the parts of each compilation unit only once, immediately translating each part into its final machine code. ... This refers to the logical functioning of the compiler, not to the actual reading of the source file once only.

Explanation:

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What is the significance of XML tags?
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your answer would be to ur question would be B

7 0
2 years ago
An organization is planning to implement a VPN. They want to ensure that after a VPN client connects to the VPN server, all traf
Sonja [21]

Answer:

B. Full tunnel.

Explanation:

In this scenario, an organization is planning to implement a virtual private network (VPN). They want to ensure that after a VPN client connects to the VPN server, all traffic from the VPN client is encrypted. The best method to meet this goal is to use a full tunnel.

A full tunnel is a type of virtual private network that routes and encrypts all traffics or request on a particular network. It is a bidirectional form of encrypting all traffics in a network.

On the other hand, a split tunnel is a type of virtual private network that only encrypts traffic from the internet to the VPN client.

Hence, the full tunnel method is the most secured type of virtual private network.

7 0
2 years ago
Recall that within the ArrayBoundedQueue the front variable and the rear variable hold the indices of the elements array where t
Citrus2011 [14]

Answer:

int n = elements.length;

if(rear < n) {

rear = (rear + 1) % n;

elements[rear] = element;

rear = rear + 1;

}

Explanation:

Options are not made available; However, I'll answer the question base on the following assumptions.

Assumptions

Array name = elements

The front and the rear variable hold the current indices elements

Element to enqueue is "element" without the quotes

To enqueue means to add an element to an already existing queue or to a new queue.

But first, the queue needs to be checked if it can accept a new element or not; in other words, if it's full or not

To do this, we check: if rear < the length of the queue

If this statement is true then it means the array can accept a new element; the new element will be stored at elements[rear] and the rear will be icremented by 1 rear by 1

Else if the statement is false, then an overflow is said to have occurred and the element will not be added.

Going by the above explanation, we have

int n = elements.length;

if(rear < n) {

rear = (rear + 1) % n;

elements[rear] = element;

rear = rear + 1;

}

Additional explanation:

The first line calculates the length of the queue

The if condition on line 2 tests if the array can still accept an element or not

Let's assume this statement is true, then we move to liine 3

Line 3 determines the new position of rear.

Let's assume that n = 6 and current rear is 4.

Line 3 will produce the following result;

rear = (rear + 1) % n;

rear = (4 + 1)% 6

rear = 5%6

rear = 5.

So, the new element will be added at the 5th index

Then line 4 will be equivalent to:

elements[rear] = element;

elements[5] = element;

Meaning that the new element will be enqueued at the 5th index.

Lastly, rear is incremented by 1 to denote the new position where new element can be added.

6 0
3 years ago
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