Question

Find y of this shape.

Answer 1

as shown in figure LN = KN

triangle KLN is right angle triangle so using Pythagoras theorem

KL^2 = LN^2 + KN^2

KL^2 = LN^2 + LN^2 = 2LN^2

KL = √(2LN^2)

y = LN√2

now lets find value of LN

now LMN is also right angle triangle so using trigonometry

MN/LN = sin 30

putting value of MN=5 and sin 30 which is 1/2

5/LN = 1/2

LN = 5×2= 10

putting it back in our first equation

y = LN√2

y = 10√2