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alexira [117]
3 years ago
14

In the diagram, the length of segment VS is 39 units.

Mathematics
2 answers:
s2008m [1.1K]3 years ago
8 0
It is given that the segment TR is equal to the segment VR, so segment VS is also equal to segment TS  
VS = TS
39 = 6x – 3
39 + 3 = 6x
42 = 6x
X = 7  

TV = 2(VR)
TV = 2 ( 2(7) + 5)
<span>TV = 38 units</span>
kap26 [50]3 years ago
3 0

Answer:

the answer is 38 units

Step-by-step explanation:

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Step-by-step explanation:

7 0
3 years ago
8) through: (-3, -2), perp. to y = x – 1<br> A) y=-5x – 1 B) y=-4x – 5<br> C) y=-x – 5 D) y=-5x – 4
nexus9112 [7]

<u>Answer:</u>

The equation through (-3, -2) and perpendicular to y = x – 1 is y = -x -5 and option c is correct.

<u>Solution:</u>

Given, line equation is y = x – 1 ⇒ x – y – 1 = 0. And a point is (-3, -2)

We have to find the line equation which is perpendicular to above given line and passing through the given point.

Now, let us find the slope of the given line equation.

\text { Slope }=\frac{-x \text { coefficient }}{y \text { coefficient }}=\frac{-1}{-1}=1

We know that, <em>product of slopes of perpendicular lines is -1. </em>

So, 1 \times slope of perpendicular line =  -1

slope of perpendicular line = -1

Now let us write point slope form for our required line.

\mathrm{y}-\mathrm{y}_{1}=\mathrm{m}\left(\mathrm{x}-\mathrm{x}_{1}\right)

y – (-2) = -1(x – (-3))

y + 2 = -1(x + 3)

y + 2 = -x – 3

x + y + 2 + 3 = 0

x + y + 5 = 0

y = -x -5

Hence the equation through (-3, -2) and perpendicular to y = x – 1 is y = -x -5 and option c is correct.

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