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3 years ago

{c, f , j, k}={j, k, f , c }

Mathematics

2 answers:

frutty [35]3 years ago

3 0

Answer:

True.

Step-by-step explanation:

These are sets containing the same exact elements so they are the same set of elements.

They both contain 4 elements.

The 4 elements in each are c, f , j , and k.

It matters not of the arrangement. It also doesn't matter if they repeat an element.

For example these sets are also the same:

{a,a,b} and {a,b}.

They both contain 2 elements and those elements are a and b.

People don't normally write something like {a,a,b} because it is redundant (because of the repetition of a).

Here is an example of some sets that are equal:

{1,2,3}={1,3,2}={2,1,3}={2,3,1}={3,1,2}={3,2,1}.

These are all the same because they all contain the elements: 1 , 2 , and 3. It doesn't matter the order in a set.

Xelga [282]3 years ago

3 0

It is True because it is the same thing except the other elements are rearranged

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If you're using the app, try seeing this answer through your browser: brainly.com/question/2822772

_______________

Evaluate the indefinite integral:

$\mathsf{\displaystyle\int\! \frac{cos\,x}{sin^2\,x}\,dx}\\\\\\
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$\therefore~~\boxed{\begin{array}{c}\mathsf{\displaystyle\int\! \frac{cos\,x}{sin^2\,x}\,dx=-\,csc\,x+C} \end{array}}\qquad\quad\checkmark$

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Tags: <em>indefinite integral substitution trigonometric trig function sine cosine cosecant sin cos csc differential integral calculus</em>

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​{c​, f ​, ​j, ​k}=​{j, ​k, f ​, c ​}

{c, f , j, k}={j, k, f , c }