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Kruka [31]
3 years ago
8

Simplify open parentheses x to the 2 ninths power close parentheses to the 3 eighths power

Mathematics
2 answers:
Nostrana [21]3 years ago
6 0
\bf a^{\frac{{ n}}{{ m}}} \implies  \sqrt[{ m}]{a^{ n}} \qquad \qquad
\sqrt[{ m}]{a^{ n}}\implies a^{\frac{{ n}}{{ m}}}\\\\
-------------------------------\\\\
\left( x^{\frac{2}{9}} \right)^{\frac{3}{8}}\implies x^{\frac{2}{9}\cdot \frac{3}{8}}\implies x^{\frac{6}{72}}\implies x^{\frac{1}{12}}\implies \sqrt[12]{x}
TEA [102]3 years ago
4 0
<span>If this is correct: (x^(2/9))^(3/8) 
Then it would be x^(1/12)</span>
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5-3+2 any answers? Pls idk it help please
alina1380 [7]

Answer:

5-3+2=4

Step-by-step explanation:

5-3=2

2+2=4

4 0
3 years ago
Read 2 more answers
Between the two of them, they teach 35 yoga classes each week. if erica teaches 13 fewer than twice as many as bo, how many clas
Nutka1998 [239]
Assume x are Erica's classes & y are Bo's classes.
x+y=35
x=2y-13
Replacing the value of x into the first equation
2y-13+y=35
3y=35+13
y=16 classes
x=2*16-13=19 classes
7 0
3 years ago
Question 7 (points) ∠DBC ≅ True or False
muminat

Answer:

answer is false okkkkm

4 0
4 years ago
If b is the midpoint of ac, ab=12x+11 and bc= 14x - 1, find AB
xxMikexx [17]

Answer:

AB = 83

Step-by-step explanation:

The mid-point of any segment divides the segment into two equal parts

∵ B is the midpoint of segment AC

→ That means B divides AC into two equal segments AB and BC

∴ AB = BC

∵ AB = 12x + 11

∵ BC = 14x - 1

→ Equate them

∴ 14x - 1 = 12x + 11

→ Subtract 12x from both sides

∵ 14x - 12x - 1 = 12x - 12x + 11

∴ 2x - 1 = 11

→ Add 1 to both sides

∵ 2x - 1 + 1 = 11 + 1

∴ 2x = 12

→ Divide both sides by 2

∵ \frac{2x}{2}=\frac{12}{2}

∴ x = 6

→ To find AB substitute x by 6 in its expression

∵ ab = 12x + 11

∵ x = 6

∴ AB = 12(6) + 11

∴ AB = 72 + 11

∴ AB = 83

3 0
4 years ago
Ayuda necesito resolver este problema con procedimiento ;)
Paraphin [41]

x^3-2x^2+x-1 is one of the prime factors of the polynomial

<h3>How to factor the expression?</h3>

The question implies that we determine one of the prime factors of the polynomial.

The polynomial is given as:

x^8 - 3x^6 + x^4 - 2x^3 - 1

Expand the polynomial by adding 0's in the form of +a - a

x^8 - 3x^6 + x^4 - 2x^3 - 1 = x^8 -2x^7 + 2x^7 - 4x^6 +x^6 + 2x^5 -2x^5- 3x^4 + 4x^4 + 2x^3 -6x^3+2x^3- x^2  -3x^2 +4x^2-2x+2x-1

Rearrange the terms

x^8 - 3x^6 + x^4 - 2x^3 - 1 = x^8 -2x^7 + 2x^5 - 3x^4 + 2x^3 - x^2 + 2x^7 - 4x^6 + 4x^4 -6x^3+4x^2-2x+x^6-2x^5+2x^3-3x^2+2x-1

Factorize the expression

x^8 - 3x^6 + x^4 - 2x^3 - 1 = x^2(x^6-2x^5+2x^3-3x^2+2x-1) + 2x(x^6-2x^5+2x^3-3x^2+2x-1) + 1(x^6-2x^5+2x^3-3x^2+2x-1)

Factor out x^6-2x^5+2x^3-3x^2+2x-1

x^8 - 3x^6 + x^4 - 2x^3 - 1 = (x^2+2x + 1)(x^6-2x^5+2x^3-3x^2+2x-1)

Express x^2 + 2x + 1 as a perfect square

x^8 - 3x^6 + x^4 - 2x^3 - 1 = (x+1)^2(x^6-2x^5+2x^3-3x^2+2x-1)

Expand the polynomial by adding 0's in the form of +a - a

x^8 - 3x^6 + x^4 - 2x^3 - 1 = (x+1)^2(x^6- 2x^5+x^4-x^4-x^3 +x^3-2x^3-x^2 -2x^2 +x+x - 1)

Rearrange the terms

x^8 - 3x^6 + x^4 - 2x^3 - 1 = (x+1)^2(x^6- 2x^5+x^4-x^3-x^4-2x^3-x^2+x+x^3-2x^2 +x - 1)

Factorize the expression

x^8 - 3x^6 + x^4 - 2x^3 - 1 = (x+1)^2(x^3(x^3-2x^2+x-1) -x(x^3-2x^2+x-1)+1(x^3-2x^2+x-1))

Factor out x^3-2x^2+x-1

x^8 - 3x^6 + x^4 - 2x^3 - 1 = (x+1)^2(x^3 -x+1)(x^3-2x^2+x-1)

One of the factors of the above polynomial is x^3-2x^2+x-1.

This is the same as the option (c)

Hence, x^3-2x^2+x-1 is one of the prime factors of the polynomial

Read more about polynomials at:

brainly.com/question/4142886

#SPJ1

4 0
2 years ago
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