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ziro4ka [17]
3 years ago
12

Write this number in word form

Mathematics
2 answers:
san4es73 [151]3 years ago
8 0
Threes hundred and ten million,seven hundred and sixty three thousand,one hundred and thirty six
expeople1 [14]3 years ago
3 0
Ok its it is three hundred million seven hundred sixty three one hundred thirty six
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[Exponential] |x|-2|-1|0|1|2| |y|2/9|2/3|2|6|18| When the x-value increases by 1, the y-value ________ (b-value)
dimaraw [331]

Answer:

b = 3

The value of y triples

Step-by-step explanation:

Given:

\begin{array}{cccccc}x & {-2} & {-1} & {0} & {1} & {2} \ \\ y & {\frac{2}{9}} & {\frac{2}{3}} & {2} & {6} & {18} \ \end{array}

Required

Determine b value

An exponential equation is:

y = ab^x

When x = 0; y =2

So:

y = ab^x

2 = a * b^0

2 = a

a = 2

When x = 2; y = 18

So:

18 = a * b^2

Substitute 2 for a

18 = 2 * b^2

Divide by 2

9 =  b^2

Take positive square roots of both sides

3 = b

b = 3

5 0
3 years ago
The germination rate is the rate at which plants begin to grow after the seed is planted.
chubhunter [2.5K]

Answer:

z=\frac{0.467 -0.9}{\sqrt{\frac{0.9(1-0.9)}{15}}}=-5.59  

p_v =P(z  

So the p value obtained was a very low value and using the significance level given \alpha=0.05 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the proportion of germinated seeds is significantly lower than 0.9 or 90%

Step-by-step explanation:

Data given and notation

n=15 represent the random sample taken

X=7 represent the number of seeds germinated

\hat p=\frac{7}{15}=0.467 estimated proportion of seeds germinated

p_o=0.9 is the value that we want to test

\alpha represent the significance level

z would represent the statistic (variable of interest)

p_v represent the p value (variable of interest)  

Concepts and formulas to use  

We need to conduct a hypothesis in order to test the claim that the true proportion of germinated seeds is less than 0.9 or 90%.:  

Null hypothesis:p\geq 0.9  

Alternative hypothesis:p < 0.9  

When we conduct a proportion test we need to use the z statisitc, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.

Calculate the statistic  

Since we have all the info requires we can replace in formula (1) like this:  

z=\frac{0.467 -0.9}{\sqrt{\frac{0.9(1-0.9)}{15}}}=-5.59  

Statistical decision  

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.  

The significance level assumed is \alpha=0.05. The next step would be calculate the p value for this test.  

Since is a left tailed test the p value would be:  

p_v =P(z  

So the p value obtained was a very low value and using the significance level given \alpha=0.05 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the proportion of germinated seeds is significantly lower than 0.9 or 90%

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3 years ago
Which function is represented by the graph below?
Bad White [126]
Good day ~_~ /////////////

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Line CD passes through points C(3, -5) And D(6, 0). What is the equation of line CD in standard form?
Fynjy0 [20]
Y = mx + b
m = (0 - -5)/(6 - 3) = 5/3
y = 5/3x + b
0 = 5/3(6) + b
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(y = 5/3x - 10)3
3y = 5x - 30
3y - 5x = -30
5x - 3y = 30
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Jala put $600 in an interest bearing account with a annual compound interest rate of 5%. Jala determined that after seven years,
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14 years. Would be your answer.


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