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san4es73 [151]
3 years ago
7

Solve for the exact value of x.

Mathematics
2 answers:
qaws [65]3 years ago
5 0
Use the a² + b² = c² formula

c = x
b = 5
a = 8 

(Note: C must always be the hypotenuse, however b and a are interchangeable)

a² + b² = c²
(8)² + (5)² = x²
64 + 25 = x²
x² = 89

square root both sides to isolate the x

x² = 89
√x² = √89
x = √89 or 9.43398

hope this helps
forsale [732]3 years ago
3 0
A² + b² = c²
5² + 8² = x²
x² = 25 + 64
x² = 89
x = √89
x = 9.43
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Answer:

y=-\dfrac{13}{49}x^2

Step-by-step explanation:

The shape of an arch corresponds to a parabola.

the general equation for a parabola is:

y=ax^2+bx+c

we're given three coordinates: (-7,-13),(7,-13) and (0,0)

so we can plug these values in the general equation to make 3 separate equations:

(x,y) = (-7,-13)

-13=a(-7)^2+b(-7)+c

49a-7b+c=-13

(x,y) = (7,-13)

-13=a(7)^2+b(7)+c

49a+7b+c=-13

(x,y) = (0,0)

0=a(0)^2+b(7)+c

c=0

so we have three equations. and we can solve them simultaneously to find the values of a,b, and c.

we've already found c = 0, let's use substitute it to other equations.

49a-7b+c=-13\quad\Rightarrow\quad49a-7b=-13

49a+7b+c=-13\quad\Rightarrow\quad49a+7b=-13

we can solve these two equation using the elimination method, by simply adding the two equations

\quad\quad49a-7b=-13\\+\quad49a+7b=-13

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\quad\quad 98a=-26

\quad\quad a=-\dfrac{13}{49}

Now we can plug this value of a in any of the two equations.

49a-7b=-13

49\left(-\dfrac{13}{49}\right)-7b=-13

-13-7b=-13

-7b=0

b=0

We have the values of a,b, and c. We can plug them in the general equation to find the equation of the arch.

y=\left(-\dfrac{13}{49}\right)x^2+0x+0

y=-\dfrac{13}{49}x^2

49y=-13x^2

This our equation of the arch!

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Svetach [21]

Answer:

Step-by-step explanation:

First what we must do is rewrite the table to find a solution:

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Answer:

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Now, X=VY+YK

Substituting the values, we get

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2 years ago
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