1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
marishachu [46]
3 years ago
5

4y+12=0 How do I get the two points to be graphed

Mathematics
1 answer:
coldgirl [10]3 years ago
8 0

Did somebody say you're supposed to draw the graph of the equation ?
Is that the assignment ?

OK.  Just like every other equation you need to graph, get it in the
standard form, where 'y' is all alone on one side, and everything else
is on the other side.  When you do that, you'll be able to spot the slope
and y-intercept of the  line, or get some points, or whatever you want.

                                               4y + 12  =  0

Subtract 12 from each side:          4y  =  -12

Divide each side by 4:                      y  =  -3

There's the equation you can handle. 
The y-intercept is -3, and the slope is zero.

Would you like some points ?  OK.  Pick a couple of values for 'x',
and calculate the value of 'y' for each one:

The first value I picked for 'x':  x = 72 
The equation is  y=-3, so when x=72, y=-3.  The point is (72, -3)

The second value I picked for 'x' is:  x = 1
The equation is  y=-3, so when x=1,  y=-3.    The second point is (1, -3).

The third value I picked for 'x' is 4 billion.
The equation is  y=-3, so when x=4 billion, y=-3.  The third point is  (1, -3).

Do you see what's going on here ?  Your original equation didn't even
have 'x' in it, so we could tell right away that when the graph is drawn,
the value of 'y' at every point can't depend on 'x'.

When we simplified the equation and got it in standard form, we found that
the slope of the graph is zero.  That means the graph doesn't rise or fall ...
it's just a horizontal line.  Sure enough, the height of points on the line
doesn't depend on 'x'.  The value of 'y' at every point on the line is  -3 .
You might be interested in
Matt had a full jar of marbles. He gave Kayla 3/4 of the marbles. Then Kayla returned 1/3 of a jar's worth of marbles to the jar
Aleks [24]
Full jar of marbles, <span>He gave Kayla 3/4 of the marbles so 1/4 left
</span><span>Then Kayla returned 1/3 of a jar's worth of marbles to the jar

1/4 + 1/3 = 3/12 + 4/12 = 7/12

Answer: 7/12 jar of marbles now.</span>
8 0
3 years ago
Read 2 more answers
Find the two square roots of each complex number by creating and solving polynomial equations.
son4ous [18]

Answer:

1) w₁=4 - i w₂= -4 + i

2) w₁= 3 - i w₂= -3  + i

3) w₁= 1 + 2i w₂= - 1 - 2i

4) w₁= 2- 3i w₂= -2 + 3i

5) w₁= 5 - 2i w₂= -5 + 2i

6) w₁= 5 - 3i w₂= -5 + 3i

Step-by-step explanation:

The root of a complex number is given by:

\sqrt[n]{z}=\sqrt[n]{r}(Cos(\frac{\theta+2k\pi}{n}) + i Sin(\frac{\theta+2k\pi}{n}))

where:

r: is the module of the complex number

θ: is the angle of the complex number to the positive axis x

n: index of the root

1) z = 15 − 8i  ⇒ r=17 θ= -0.4899 rad

w₁=\sqrt{17}(Cos(\frac{-0.4899}{2}) + i Sin(\frac{-0.4899}{2}))=4-i

w₂=\sqrt{17}(Cos(\frac{-0.4899+2\pi}{2}) + i Sin(\frac{-0.4899+2\pi}{2}))=-1+i

2) z = 8 − 6i  ⇒ r=10 θ= -0.6435 rad

w₁=\sqrt{10}(Cos(\frac{ -0.6435}{2}) + i Sin(\frac{ -0.6435}{2}))= 3 - i

w₂=\sqrt{10}(Cos(\frac{ -0.6435+2\pi}{2}) + i Sin(\frac{ -0.6435+2\pi}{2}))= -3  + i

3) z = −3 + 4i  ⇒ r=5 θ= -0.9316 rad

w₁=\sqrt{5}(Cos(\frac{-0.9316}{2}) + i Sin(\frac{-0.9316}{2}))= 1 + 2i

w₂=\sqrt{5}(Cos(\frac{-0.9316+2\pi}{2}) + i Sin(\frac{-0.9316+2\pi}{2}))= -1 - 2i

4) z = −5 − 12i  ⇒ r=13 θ= 0.4426 rad

w₁=\sqrt{13}(Cos(\frac{0.4426}{2}) + i Sin(\frac{0.4426}{2}))= 2- 3i

w₂=\sqrt{13}(Cos(\frac{0.4426+2\pi}{2}) + i Sin(\frac{0.4426+2\pi}{2}))= -2 + 3i

5) z = 21 − 20i  ⇒ r=29 θ= -0.8098 rad

w₁=\sqrt{29}(Cos(\frac{-0.8098}{2}) + i Sin(\frac{-0.8098}{2}))= 5 - 2i

w₂=\sqrt{29}(Cos(\frac{-0.8098+2\pi}{2}) + i Sin(\frac{-0.8098+2\pi}{2}))= -5 + 2i

6) z = 16 − 30i ⇒ r=34 θ= -1.0808 rad

w₁=\sqrt{34}(Cos(\frac{-1.0808}{2}) + i Sin(\frac{-1.0808}{2}))= 5 - 3i

w₂=\sqrt{34}(Cos(\frac{-1.0808+2\pi}{2}) + i Sin(\frac{-1.0808+2\pi}{2}))= -5 + 3i

6 0
3 years ago
What is 1 and 3/4 divided by 4/5​
icang [17]

Answer:

The answer is 2 and 3/16

6 0
3 years ago
Why would a bank want to loan someone money?
AVprozaik [17]

Answer: So they can help someone with good credit score

Step-by-step explanation:

4 0
2 years ago
Read 2 more answers
HELP ASAP!! 10 minuets left! lots of points
VLD [36.1K]

Answer:

130 yd^2

Step-by-step explanation:

First we find the area of the triangle

A = 1/2 b h  where b is 10 and h= 6.25

A = 1/2 (10) * 6.25

   = 31.25 yd^2

Then we find the area of rectangle A

A = l*w  where l is 10 and w = (7.5-2.5) = 5

A = 10 * 5

   = 50 yd^2

Then we find the area of rectangle B

A = l*w  where l is 6.5 and w = 7.5

A = 6.5 * 7.5

   = 48.75 yd^2

The total area is found by adding them together

A triangle + rectangle A  + rectangle B

31.25+50 + 48.75

130 yd^2

5 0
3 years ago
Other questions:
  • 9/10 miles in 5 minutes At this rate how many miles can he in in one minute
    12·1 answer
  • Jack birthday is in 6 weeks how many day is it until jacks birthday? Complete the explanation on how you could use a number line
    13·1 answer
  • Which equation represents the general form of a circle with a center at (-2,-3) and a diameter of 8 units
    6·2 answers
  • Mrs. Martin directs two courses one chorus has 28 students the other chorus has 36 students for rehearsals she wants to divide e
    7·1 answer
  • Helppppppppppppppppppppppppppppppppppppp
    6·1 answer
  • What is equivalent to 6(3n-4)
    15·1 answer
  • Simplify 6 - 2 3 + (-9 + 5) · 2.
    14·2 answers
  • Porpotions and percents I NEED HELP THIS IS DUE TODAY!!!!​
    14·1 answer
  • Which equation is equivalent to y=x^2+6x+7
    9·1 answer
  • If a researcher needs a sample that is representative of the population they are studying, they could utilize a _______.
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!