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3 years ago

Simplify the equation.

Mathematics

2 answers:

artcher [175]3 years ago

7 0

Answer:

4x+30.97777... (7 repeating)

Step-by-step explanation:

Look at image

alex41 [277]3 years ago

5 0

That’s the correct answer ^

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Find the value of x.

hjlf

Answer:

Step-by-step explanation:

I realize that the time is passed.... but FYI

BD is Geometric Mean

That's mean BD² = 6 × 5 = 30 ⇒ BD = √30

x² = BD² + 6² = 30 + 36 = 66 ⇒ x = √66

y = √55

5 0

2 years ago

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Help i'll mark brainliest

tensa zangetsu [6.8K]

The correct answer is D. 40

4 0

2 years ago

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The organization sent

ValentinkaMS [17]

Answer:

<h2>The percentage of the people invited attended the fundraising event is 69.33%.</h2>

Step-by-step explanation:

To find the percentage of those who attended the fundraising event, simply divide the number of attendees to the total number invited.

$\frac{416}{640} = 0.69333333 = \boxed{69.33\%}$

7 0

2 years ago

Only a very small (<5) percentage of measurements can be more than 2 standard deviations from the mean of the normal distribu

horsena [70]

Answer:

A. True

Step-by-step explanation:

The empirical rule in statistics states that:

68% of the data will be within 1 standard deviation
95% of the data will be within 2 standard deviations
99.7% of the data will be within 3 standard deviations

So yes, we can state that 5% or less of the data will be more than 2 standard deviations away from the mean. Of course, statistics is not 100% certain, so this rule is not 100% right all the time. Some exceptions might result, but generally speaking, the results should follow the empirical rule.

5 0

2 years ago

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True or False: A race car driver tested his car for time from 0 to 60 mph, and in 20 tests obtained an average of 4.85 seconds w

vredina [299]

Answer:

False

Step-by-step explanation:

given that a race car driver tested his car for time from 0 to 60 mph, and in 20 tests obtained an average of 4.85 seconds with a standard deviation of 1.47 seconds.

Sample size n = 20

since population standard deviation is not known, we can use t critical value for finding out the confidence interval

df=19

t critical = 2.045

Margin of error = $2.045*\frac{s}{\sqrt{n} } \\=2.045*\frac{1.47}{\sqrt{20} } \\=0.6722$

conidence interval = Mean±Margin of error

= $(4.85-0.6722, 4.85+0.6722)\\= (4.1778, 5.5222)$

The given confidence interval is (4.52, 5.18)

Hence the statement is false.

5 0

3 years ago