Question

What is the solution set of this equation? I appreciate any help!! Thankyou!

Answer 1

Hello from MrBillDoesMath!

Answer:  -3 and 2

Discussion:

The equation to solve is:

6/m + 2 = (m+3)/(m-1)

Multiple both sides by m * (m-1).

6/m * (m*(m-1))  + 2 m (m-1) =  (m+3)/(m-1) * (m(m-1))

Simplify:

6 (m-1) + 2 m (m-1) =   (m+3)*m =>

6m -6 + 2m^2 - 2m = m^2 + 3m =>

2m^2 +4m - 6 =  m^2 + 3m.  Subtract m^2 and 3m from both sides

m^2 + m - 6 = 0. Factor this equation.

(m +3) ( m-2) = 0 so the solution  set is  -3 and 2

Thank you,

MrB