Question

QUICK need help with this

Answer 1

QR = ST = 480...eqn 1

CU = 5x...eqn 2

CV = 9x -56...eqn 3

CR = CT = radius of circle

UR = O.5 QR

VT = 0.5 ST

from eqn 1...UR = VT

=> UR = VT

thus CU = CV

Subs eqn 1 into eqn 2

=> 9x -56 = 5x

=> x = 14

=> CV = 9(14) - 56 = 70 = CU

Using a^2 + b^2 = c^2

=> c^2 = 70^2 + 240^2

=> c^2 = 4900 + 57600 = 62500

=> c = 250

radius of circle is 250