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yaroslaw [1]
3 years ago
10

Of the 182 students who are taking three first year core Mathematics modules (Reasoning, Algebra and Calculus), 129 like Reasoni

ng, 129 like Algebra, 129 like Calculus, 85 like Reasoning and Algebra, 89 like Reasoning and Calculus, 86 like Algebra and Calculus, and 54 like all three modules. How many of the students like none of the core modules?
Mathematics
1 answer:
Natasha2012 [34]3 years ago
4 0

Answer:

1 student.

Step-by-step explanation:

No of students that like Reasoning = 129 - (85-54) - (89-54)

= 63

No of students that like Reasoning only = 63-54

= 9

No of students that like Calculus = 129 - (86-54) - (89-54)

= 62

No of students that like Calculus only = 62-54

= 8

No of students that like Algebra = 129 - (86-54) - (85-54)

= 66

No of students that like Algebra only = 66-54

= 12

No of students that like Algebra and Resoning only = (85-54)

= 31

No of students that like Algebra and Calculus only = (86-54)

= 32

No of students that like Reasoning and Calculus only =(89-54)

= 35

Total students = 182

Total students offering at least one module + total students offering none = Total students

182 = 9 + 8 + 12 + 31 + 32 + 35 + 54 + X

X = 182 - 181

= 1 student.

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Answer:

i think it 32,768

Step-by-step explanation:

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7 0
3 years ago
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If a coin is tossed 3 times, and then a standard six-sided die is rolled 4 times, and finally a group of four cards are drawn fr
PSYCHO15rus [73]

Answer:

67,365,043,200

Step-by-step explanation:

A coin toss has 2 possible outcomes.  A coin tossed 3 times has 2³ = 8 possible permutations.

A standard die has 6 possible outcomes.  A die rolled 4 times has 6⁴ = 1296 possible permutations.

The number of ways 4 cards can be chosen from a deck of 52 without replacements is 52×51×50×49 = 6,497,400.

The total number of possible outcomes is:

8 × 1296 × 6,497,400 = 67,365,043,200

3 0
4 years ago
4.. Please help. Is DE←→ perpendicular to FG←→? Why or why not?
olya-2409 [2.1K]

Given:

DE contains the points D(1, -2) and E(3, 4).

FG contains the points F(-1, 2) and G(4, 0).

To find:

Is DE perpendicular to FG.

Solution:

Slope of DE:

$m=\frac{y_2-y_1}{x_2-x_1}

Here x_1=1, y_1=-2, x_2=3, y_2=4

$m=\frac{4-(-2)}{3-1}

$m=\frac{6}{2}

m = 3

Slope of FG:

$m=\frac{y_2-y_1}{x_2-x_1}

Here x_1=-1, y_1=2, x_2=4, y_2=0

$m=\frac{0-2}{4-(-1)}

$m=\frac{-2}{4+1}

$m=\frac{-2}{5}

<em>Two lines are perpendicular if product their slopes are -1.</em>

Slope of DE × Slope of FG

         $=3\times \frac{-2}{5}

         $= \frac{-6}{5}

         ≠ -1

The solution is no, because the product of the slopes is not -1.

3 0
3 years ago
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Find the distance between the origin and the point (10,45,57)
Marina86 [1]

Answer:

Step-by-step explanation:

3D space  (x, y, z)  = (10, 45, 57)

I will use  x² + y² = (2D Hyp)²  and (2D Hyp)² + z² = (3D Hyp)²

which is just x² + y²  + z² = (3D Hyp)²

10² + 45²  + 57² = (3D Hyp)²

100 + 2025 + 3249    =  5374   =   (3D Hyp)²    the destance from the origin

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3 0
3 years ago
PLEASE HELP
Dmitriy789 [7]

Answer:

(-1.5,-16)

(1,4)

(2.5,-3)

Step-by-step explanation:

Over the interval (-3,0], the local minimum is (-1.5,-16).

Over the interval [0,3], the local maximum is (1,4).

Over the interval [0,57 , the local minimum is (2.5,-3).

4 0
3 years ago
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