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NARA [144]
3 years ago
9

PLEASE HELP !!!! ILL GIVE BRAINLIEST !!!

Mathematics
2 answers:
Harrizon [31]3 years ago
8 0

Answer: The answer to the first question is measure 3 is 79 degrees. For the second one the angles are known as corresponding angles.

Step-by-step explanation:

Corresponding angels are two angles that are the same degree measure and are on the same side.

kogti [31]3 years ago
7 0

Answer:

<3 is 79 degrees and they are corresponding angles

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Please help me answer theseeeee
Tresset [83]

Answer:

Noah ran faster noah ran 8 and 1/3 in 1 hour

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Please help! Or if someone can explain how to find the answer
VARVARA [1.3K]

Answer:

If the equation is in the form, ax + b = c, where x is the variable, you can solve the equation as before. First “undo” the addition and subtraction, and then “undo” the multiplication and division. Solve 3y + 2 = 11. Subtract 2 from both sides of the equation to get the term with the variable by itself.

Answer: x = 20

All this is exaple hople it help

5 0
3 years ago
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Answer number 1 and use the lattice board I set up
Aneli [31]
6*3=18
5*3=15
6*4=24
5*4=20
then you would add the columns and you would get 1,904
It would be easier to show you.
7 0
3 years ago
What is the area of the regular hexagon ABCEF? Explain your reasoning.
Reil [10]

Answer:

1350\sqrt{3} units²

Step-by-step explanation:

The regular hexagon consists of 6 equiangular triangles

The area (A) of a equilateral triangle is calculated as

A = \frac{s^2\sqrt{3} }{4} ( s is the side length )

Here s = 30 , then

A = \frac{30^2\sqrt{3} }{4} = \frac{900\sqrt{3} }{4} = 225\sqrt{3} units²

Thus the area of the regular hexagon is

area = 6 × 225\sqrt{3}

        = 1350\sqrt{3} units² ← exact value

         ≈ 2338.3 units² ( to 1 dec. place )

4 0
2 years ago
URGENT! WILL GIVE BRAINLY FOR CORRECT ANSWER
Minchanka [31]

Answer:

sorry if im wrong i think wrong numbers. plz check

Step-by-step explanation:

The center of dilation of the question is (-4,-3) .

let say that

x0=-4

y0=-3

Label the image A'B'C'

The new coordinate would be

A(-4,-1)

x=4

y=-1

x'=x0+ 2(x - x0)

x'= -4+ 2(-4 +4)

x'=-4

y'=y0+ 2(y - y0)

y'= -3+ 2(-1 +3)

y'=-3 +4= 1

______________________________

B(-4,-3)

x=-4

y=-3

x'=x0+ 2(x - x0)

x'= -4+ 2(-4 +4)

x'=-4

y'=y0+ 2(y - y0)

y'= -3+ 2(-3 +3)

y'=-3

______________________________

C(-1,-3)

x=-1

y=-3

x'=x0+ 2(x - x0)

x'= -4+ 2(-1 +4)

x'=-4 +6= 2

y'=y0+ 2(y - y0)

y'= -3+ 2(-3 +3)

y'=-3

A'(-4,1)

B'(-4,-3)

C'(2,-3)

3 0
2 years ago
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