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kenny6666 [7]
3 years ago
7

What are the exact solutions of x^2 = 5x + 2?

Mathematics
1 answer:
aleksandrvk [35]3 years ago
5 0
Move everybody to one side
minus 5x+2 both sides
x^2-5x-2=0
use quadratic formula where
if you have
ax^2+bx+c=0
x=\frac{-b+/- \sqrt{b^{2}-4ac} }{2a}

1x^2-5x-2=0
a=1
b=-5
c=-2

x=\frac{-(-5)+/- \sqrt{(-5)^{2}-4(1)(-2)} }{2(1)}
x=\frac{5+/- \sqrt{25+8} }{2}
x=\frac{5+/- \sqrt{33} }{2}

aprox
x=5.372281323 or -0.3722813233
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Write the equation of a line in slope intercept form that is perpendicular to the line y = –4x and passes through the point (2,
Gnesinka [82]

1. If the line that we are searching for is perpendicular to the line y = -4x, this means that the gradient of our line and the gradient of the perpendicular line will multiply to give -1. Thus if we call the gradient of our line m, then:

m*(-4) = -1

-4m = -1

m = 1/4

2. Since we know that m = 1/4 and we have a point (2,6) on our line, we can use the formula y - y1 = m(x - x1) to find the equation of our line, where (x1, y1) is the coordinates of a point on the line. Thus:

y - y1 = m(x - x1)

y - 6 = (1/4)(x - 2)

y - 6 = (1/4)x - 2/4 (Expand (1/4)(x - 2))

y = (1/4)x - 1/2 + 6 (Simplify 2/4 and add 6 to each side)

y = (1/4)x + 11/2 (Evaluate -1/2 + 6)

Slope-intercept form is given by y = mx + c. As our equation is already in this form, there is nothing more to do. Thus, the answer is y = (1/4)x + 11/2

6 0
3 years ago
If PQ=8 and Q lies at -13 where could P be located?
choli [55]

Answer:

In the given figure the point on segment PQ is twice as from P as from Q is. What is the point? Ans is (2,1).

Step-by-step explanation:

There is really no need to use any quadratics or roots.

( Consider the same problem on the plain number line first.  )

How do you find the number between 2 and 5 which is twice as far from 2 as from 5?

You take their difference, which is 3. Now splitting this distance by ratio 2:1 means the first distance is two thirds, the second is one third, so we get

4=2+23(5−2)

It works completely the same with geometric points (using vector operations), just linear interpolation: Call the result R, then

R=P+23(Q−P)

so in your case we get

R=(0,−1)+23(3,3)=(2,1)

Why does this work for 2D-distances as well, even if there seem to be roots involved? Because vector length behaves linearly after all! (meaning |t⋅a⃗ |=t|a⃗ | for any positive scalar t)

Edit: We'll try to divide a distance s into parts a and b such that a is twice as long as b. So it's a=2b and we get

s=a+b=2b+b=3b

⇔b=13s⇒a=23s

7 0
3 years ago
Please help! (image is for question 3)
nika2105 [10]

The formula for the total sum of the inner angles of the polygon is

Sn= (n-2) 180°

1) S6= (6-2) 180 = 4*180 = 720° In the hexagon all angles are equal

α= S6/6= 720/6= 120°

2) In each polygon the sum of the external angles is 360°

3) S5= (5-2) 180 = 540° than  we can add up all angles

x+131+108+107+110=540 => x= 540-456= 84°

4) α = 360/5=72°

Good luck!!!


6 0
3 years ago
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Solve for x and solve for y
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I just noticed it is A

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