2 years ago

If f(x) = 1/x^2 -1, then f(1/a+1)=

Mathematics

1 answer:

Bas_tet [7]2 years ago

8 0

Step-by-step explanation:

step 1. f(1/(a + 1)) = 1/(1/(a + 1))^2 - 1

step 2. f(1/(a + 1)) = 1/(1/(a + 1)^2) - 1

step 3. f(1/(a + 1)) = (a + 1)^2 - 1

step 4. f(1/(a + 1)) = a^2 + 2a + 1 - 1

step 5. f(1/(a + 1)) = a^2 +2a

step 6. f(1/(a + 1)) = a(a + 2)

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Solve:<br> a.) 5(x - 2) > -15<br> AND<br> b.) x/1 - 9 < -10

uysha [10]

Answer:

a.) x>-1

b.) x/1 - 9 < -10

Step-by-step explanation:

a.)

5(x - 2) > -15

(divide both sides)

x-2>-3

(move the constant to the right)

x>-3+2

(calculate)

x>-1

(answer)

b.)

x/1 - 9 < -10

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x-9<-10

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x<-10+9

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2 years ago

Determine a quadratic equation, in standard form, that has the pair of root: x=-3, x=5

Mama L [17]

Answer:

$x^2 -2x -15=0$

Step-by-step explanation:

$\text{Given that, the roots are,}~ \alpha=-3 ~ \text{and}~ \beta=5 .\\\\\text{The quadratic equation with roots}~ \alpha ~ \text{and}~ \beta ~ \text{is,}\\\\~~~~~~~~x^2 - (\alpha + \beta )x +\alpha \beta = 0\\\\\implies x^2-(-3 +5) x +(-3)(5) = 0\\\\\implies x^2 -2x -15=0$