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Hoochie [10]
3 years ago
9

Question 30Explain how to use a net to find the surfacearea of a three-dimensional figure ​

Mathematics
1 answer:
irinina [24]3 years ago
6 0

Answer:

1. Create a three-dimensional figure net.

2. Determine the area of each net face.

3. To calculate the surface area of the cube, add the areas of all the net's faces.

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Simplify this expression <br> (1/3 + 11/12)×2/3
alisha [4.7K]

1/3 = 4/12

(4/12 + 11/12) * 2/3

= 15/12 * 2/3

15/ 12 can also be written as 5/4

5/4 * 2/3 = 10/12

10/12 can be simplified into 5/6

Therefore, the answer is 5/6

5 0
3 years ago
1) For a field trip 11 students rode in cars and the rest filled eight buses. Which equation below will help you find how many s
Sergio039 [100]

Answer:

Number 3) 8x + 11 = 315

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3 years ago
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Pls do both for ( brainlist, thanks, and a 5 star review)
JulijaS [17]

Answer

2/3+5/6= is 1.5

Step-by-step explanation:

first do 2/3=0.66666666666

and 5/6=0.83333333333

then do 0.66666666666+0.83333333333=1.5

3 0
2 years ago
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What is the y-intercept of the graph
Veronika [31]

Answer:

12

Step-by-step explanation:

8 0
3 years ago
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Does anyone know how to solve this?
erik [133]

Answer:

A point in polar coordinates is written as (R, θ)

If we want to transform this point to rectangular coordinates, we get:

x = R*cos(θ)

y = R*sin(θ)

Now we can remember that the sine and cosine functions have a period of 2*pi, then:

cos(θ) = cos(θ + 2*pi)

or:

cos(θ) = cos(θ + 2*pi + 2*pi)

and so on.

Then the point (R, θ) is the same as (R, θ + 2*pi) and (R, θ + k*(2*pi))

where k can be any integer number.

Then if we have a point in polar coordinates:

(-4, -5*π/3)

Then another two polar representations of this point are:

(-4, -5*π/3 + 2*π) = (-4, -5*π/3 + 6*π/3) = (-4, π/3)

Now we can not add 2*π (nor subtract) because we would have an angle outside the range [-2*π, 2*π]

For example, if we have:

(-4, π/3 + 2*π) = (-4, 7*π/3)

And we can not change the value of the radius and get the coordinates for the same point.

So another representation could be something like:

(-8/2, π/3)

Where i just wrote -4 in another way.

Now, a really important point.

When working with polar coordinates, we always use R as a positive number (here you can see that R is negative) so this is not the standard notation for the polar representation of a point.

8 0
3 years ago
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