If the roots are 3, 2 and -3 then the function is created by multiplying
(x-3) * (x-2) * (x+3)
x^2 -5x +6 * (x+3)
x^3 -5x^2 +6x + 3x^2 -15x +18 = 0
x^3 -2x^2 -9x +18 = 0
Answer:
The answer to your question is: (1/2, -1/3)
Step-by-step explanation:
Elimination
10x - 15y = 10 (I)
4x + 6y = 0 (II)
Multiply (I) by 2 and (II) by -5
20x - 30y = 20
-20x - 30y = 0
Add both equations
0 - 60y = 20
y = -20/60
y = - 1/3
Substitute y in (II)
4x + 6(-1/3) = 0
4x - 2 = 0
4x = 2
x = 2/4
x = 1/2
4(1/2) + 6(-1/3) = 0
4/2 - 6/3 = 0
2 - 2 = 0
0 = 0
Answer:
see page for answer........
a common what? denominator?
