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Hoochie [10]
3 years ago
9

Question 30Explain how to use a net to find the surfacearea of a three-dimensional figure ​

Mathematics
1 answer:
irinina [24]3 years ago
6 0

Answer:

1. Create a three-dimensional figure net.

2. Determine the area of each net face.

3. To calculate the surface area of the cube, add the areas of all the net's faces.

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Please help ASAP!!!!!!!!!
algol [13]

Answer:

A = 23.6 units^2

Step-by-step explanation:

Let the base be 8 (as shown).

Find the height of the triangle:   Find the supplement of the 100 degree angle; it is (180 - 100), or 80 degrees.  The side "opposite" this 80-degree angle is the height of the triangle:

   

                               height      

sin 80 degrees = ---------------

                                    6

and so the height of the triangle is h = 6 sin 80 degrees, or 5.91 units.

The area of the triangle is found using A = (1/2)(base)(height), which here amounts to:

A = (1/2)(8 units)(5.91 units), or

                                                       A = 23.64 units^2, or A = 23.6 units^2

3 0
3 years ago
Francisca and Elizabeth are participating in a walk-a-thon fundraiser.
Ghella [55]
Francisca raises 76.50 and Elizabeth makes 43.50 together they makes 120
8 0
3 years ago
Solve for x.<br><br> x+27=−12
tiny-mole [99]
It is: x + 27 = -12
x = -12 - 27
x = -39

In short, Your Answer would be -39

Hope this helps!
8 0
3 years ago
Read 2 more answers
Colby must spend less than 275 minutes playing video games in one day. He plays different games for 25 minutes each, and Colby h
lapo4ka [179]

Answer:

A

Step-by-step explanation:

4 0
3 years ago
The product of (4z^2 + 7z - 8) and (-z + 3) is -4z^3 + xz^2 + yz - 24. What is the value of x? What is the value of y?
ycow [4]

Answer:

x=5+\frac{29}{z}-\frac{y}{z}

y=5z+29-xz

Step-by-step explanation:

Given: (4z^2+7z-8)(-z+3)=-4z^3+xz^2+yz-24; find x and y.

Let's start with finding x first. Let's distribute the left side of the equation.

-4z^3+5z^2+29z-24=-4z^3+xz^2+yz-24

Let's move everything we can to the left side of the equation. Some things will cancel out.

5z^2+29z=xz^2+yz

Now, let's move the term that includes x to the left side of the equation. Everything else should be moved to the right.

-xz^2=-5z^2-29z+yz

Let's get rid of the negative sign in front of x by dividing both sides by -1.

xz^2=5z^2+29z-yz

To get x completely isolated, divide both sides by z^2.

\frac{xz^2}{z^2}=\frac{5z^2}{z^2}+\frac{29z}{z^2}-\frac{yz}{z^2}

Simplify.

x=5+\frac{29}{z}-\frac{y}{z}

Let's solve for y. We will start with the distributed and simplified equation to make it easier.

5z^2+29z=xz^2+yz

Now, let's move the term that includes y to the left side of the equation. Everything else should be moved to the right.

-yz=-5z^2-29z+xz^2

Again, let's get rid of the negative sign in front of the y by dividing both sides by -1.

yz=5z^2+29z-xz^2

To isolate y, divide both sides by z.

\frac{yz}{z}=\frac{5z^2}{z}+\frac{29z}{z}-\frac{xz^2}{z}

Simplify.

y=5z+29-xz

8 0
3 years ago
Read 2 more answers
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