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Margarita [4]
3 years ago
5

Tech A says a camshaft position sensor must be positioned correctly to accurately signal the position of the camshaft to the pow

ertrain control module in the ignition module. Tech B says a special tool can be used to properly align the camshaft sensor or a lab scope can be used to compare the camshaft position sensor adjustment to the crankshaft position sensor. Who is correct?
Physics
1 answer:
qaws [65]3 years ago
6 0

Answer:

Both Tech A and Tech B

Explanation:

It's important to position sensor accurately to the position of camshaft to the powertrain control in the ignition module as said by Tech A. Equally, to achieve what Tech A says, a special tool can be used for comparing the position of camshaft sensor to crankshaft sensor. Therefore, both technicians are correct.

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In which arrangement of magnets will all the magnets attract?
Orlov [11]

Answer:

B

Explanation:

opposites attract ;)

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4 years ago
What kind of image is formed when an object is placed at the focal point of a convex lens? Explain WHY this is the image that oc
mariarad [96]

Answer:

Since light does not actually pass through this point, the image is referred to as a virtual image. Observe that when the object in located in front of the focal point of the converging lens, its image is an upright and enlarged image that is located on the object's side of the lens.

Explanation:

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3 years ago
Suppose there is a uniform magnetic field, B, pointing into the page (so your index finger will point into the page). If the vel
Naily [24]

Answer:

Explanation:

We shall show all given data in vector form and calculate the direction of force with the help of following formula

force F = q ( v x B )

q is charge , v is velocity and B is magnetic field.

Given B = - Bk ( i is  right  , j is  upwards  and k is straight up the page  )

v = v j

F = q ( vj x - Bk )

= -Bqvi

The direction is towards left .

a ) If velocity is down

v = - v j

F = q ( - vj x - bk )

= qvB i

Direction is right .

b ) v = v i

F = q ( vi x - Bk )

= qvB j

force is upwards

c ) v = - vi

F = q ( -vi x - Bk )

= -qvBj

force is downwards

d ) v = - v k

F = q( - vk x -Bk  )

= 0

No force will be created

e ) v =  v k

F = q(  vk x -Bk  )

= 0

No force will be created  

3 0
3 years ago
A negative charge of - 8.0 x 10^-6 C exerts an attractive force of 12 N on a second charge that is
Umnica [9.8K]

Answer:

<h2>Magnitude of the second charge is -4.17*10^{-7}C</h2>

Explanation:

According to columbs law;

F = kq1q2/r^{2}

F is the attractive or repulsive force between the charges = 12N

q1 and q2 are the charges

let q1 = - 8.0 x 10^-6 C

q2=?

r is the distance between the charges = 0.050m

k is the coulumbs constant =9*10⁹ kg⋅m³⋅s⁻⁴⋅A⁻²

On substituting the given values

12 = 9*10⁹*( - 8.0 x 10^-6)q2/0.050²

Cross multiplying

0.03=9*10^{9}*  -8.0*10^{-6} q2\\0.03 = -72*10^{3} q2\\q2 = \frac{0.03}{ -72*10^{3}} \\q2 = -4.17*10^{-7}C

6 0
4 years ago
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The variable that the experimenter decides to change to see if there is or is not an effect is the Independent Variable.
EastWind [94]
The correct answer is:  [A]:  "TRUE" .
_________________________________________________
6 0
3 years ago
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